V = x/t = 4.5 mil / 3 h = 1.5 mph
Since, v = 1.5 mph (or we can say that v is constant), distance and time vary directly and the constant of variation is 1.5 mph.
<span>Exactly 33/532, or about 6.2%
This is a conditional probability, So what we're looking for is the probability of 2 gumballs being selected both being red. So let's pick the first gumball.
There is a total of 50+150+100+100 = 400 gumballs in the machine. Of them, 100 of the gumballs are red. So there's a 100/400 = 1/4 probability of the 1st gumball selected being red.
Now there's only 399 gumballs in the machine and the probability of selecting another red one is 99/399 = 33/133.
So the combined probability of both of the 1st 2 gumballs being red is
1/4 * 33/133 = 33/532, or about 0.062030075 = 6.2%</span>
Answer:
P(X
74) = 0.3707
Step-by-step explanation:
We are given that the score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.
Let X = Score of golfers
So, X ~ N(
)
The z score probability distribution is given by;
Z =
~ N(0,1)
where,
= population mean = 73
= standard deviation = 3
So, the probability that the score of golfer is at least 74 is given by = P(X
74)
P(X
74) = P(
) = P(Z
0.33) = 1 - P(Z < 0.33)
= 1 - 0.62930 = 0.3707
Therefore, the probability that the score of golfer is at least 74 is 0.3707 .
Answer: 0.0125
Step-by-step explanation:
Given : A survey by the Pew Research Center asked a random sample of 2142 U.S. adults and a random sample of 1055 college presidents how they would "rate the job the higher education system is doing in providing value for the money.
5% the U.S. adults and 17% of the college presidents provided a rating of "Excellent."
i.e. 
, 
The standard error of the difference in sample proportions :-


Hence, the standard error of the difference in sample proportion = 0.0125