Answer:
0.665
Step-by-step explanation:
Given: 100 people are split into two groups 70 and 30. I group is given cough syrup treatment but second group did not.
Prob for a person to be in the cough medication group = 0.70
Out of people who received medication, 34% did not have cough
Prob for a person to be in cough medication and did not have cough
=
Prob for a person to be not in cough medication and did not have cough
=
Probability for a person not to have cough
= P(M1C')+P(M2C')
where M1 = event of having medication and M2 = not having medication and C' not having cough
This is because M1 and M2 are mutually exclusive and exhaustive
SO P(C') = 0.397+0.2=0.597
Hence required prob =P(M1/C') = 
Answer:
4
Step-by-step explanation:
9x=10x-4
x=4
1. 538 - 247 = ?
2. 8 - 7 = 1
3. You can't subtract 3 and 4, so you have to take number from 5 (turning it into a 4) and then you add a 1 right next to 3 (which makes it 13;13 - 4 = 9
4. 4 - 2 = 2
538 - 247 = 291
So the answer is 291.