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RoseWind [281]
3 years ago
11

Marcus states that the polynomial expression 3x3 – 4x2y + y2 + 2 is in standard form. Ariel states that it should be y2 – 4x2y +

3x3 +2. Explain which student is correct and why.
Mathematics
2 answers:
garri49 [273]3 years ago
7 0

Answer:

I know that ariel is wrong because 3x^3 is higher power than y^2

3x^3 goes first

then the mixed term -4x^2y

then the y^2

then the 2

marcus is right

Step-by-step explanation:

lora16 [44]3 years ago
4 0

Answer:

Here Ariel is wrong because 3x^3 is higher power than y^2

3x^3 goes first

then the mixed term -4x^2y

then the y^2

then the 2

So, Marcus is right

Standard form means that you write the terms by descending degree. here's main rules how to write polynomial expression in the standard form:

1. write the term with the highest exponent first (terms of third degree in our case 3x^3 );

2. write the terms with lower exponents in descending order (term -4x^2y followed by y^2 );

3. remember that a variable with no exponent has an understood exponent of 1 (here are no such terms);

4. a constant term (a number with no variable) always goes last (term 2).

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Answer:

Concept: Caclulating Standard Variables

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  4. We do (min +max + 2(Q1+median+Q3))/8
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  7. Which gives us option B
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3 years ago
Find the values of x and y. <br> (look at image)<br> x= <br><br> y=
scZoUnD [109]

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Step-by-step explanation:

I probably solved it right…

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Which point is on the graph of the equation y=2x-5?
Svetlanka [38]

Answer:

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Step-by-step explanation:

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6 0
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2(x-5)=10 but the pemdas is backwards
ale4655 [162]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Hi guys actually I have forgotten the steps do it yesterday my online school opened so I don't how to solve it can you help me p
cestrela7 [59]

Answer:

  (i)  (x +4)^3 = x^3 +12x^2 +48x +64

  (ii)  (2m +1)^3 = 8m^3 +12m^2 +6m +1

  (iii)  (a -2b)^3 = a^3 -6a^2b +12ab^2 -8b^3

Step-by-step explanation:

Powers of a binomial have a pattern. The coefficients of the terms of the expanded product are the numbers in the corresponding row of Pascal's Triangle. Here, you want the 3rd power, so the coefficients of interest are ...

  1, 3, 3, 1

The pattern is ...

  (a +b)^2 = a^2 +2ab +b^2

  (a +b)^3 = a^3 +3a^2b +3ab^2 +b^3

The total of powers of the variable is equal to the exponent of the binomial. The powers of the first variable decrease to 0 while the powers of the second variable increase from zero.

When 'a' or 'b' is something with a coefficient, that whole term is raised to the appropriate power.

__

i) (x+4)^3 = x^3 +3·4x^2 +3·4^2x +4^3

  (x +4)^3 = x^3 +12x^2 +48x +64

__

ii) (2m +1)^3 = (2m)^3 +3·1·(2m)^2 +3·1^2·(2m) +1^3

  (2m +1)^3 = 8m^3 +12m^2 +6m +1

__

iii) (a -2b)^3 = a^3 +3·a^2·(-2b) +3·a·(-2b)^2 +(-2b)^3

  (a -2b)^3 = a^3 -6a^2b +12ab^2 -8b^3

_____

<em>Additional comment on Pascal's triangle</em>

The numbers in each row are the sums of the two numbers immediately above. For binomial expansion, you're only interested in the contents of a row. The "patterns" shown in the attachment are an extra added attraction, not particularly relevant to binomial expansion.

7 0
3 years ago
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