Answer:
a) 47.55
b) 58
c) 47.88
Step-by-step explanation:
Given that the size of the orders is uniformly distributed over the interval
$25 ( a ) to $80 ( b )
<u>a) Determine the value for the first order size generated based on 0.41</u>
parameter for normal distribution is given as ; a = 25, b = 80
size/value of order = a + random number ( b - a )
= 25 + 0.41 ( 80 - 25 )
= 47.55
<u>b) Value of the last order generated based on random number (0.6)</u>
= a + random number ( b - a )
= 25 + 0.6 ( 80 - 25 )
= 25 + 33 = 58
<u>c) Average order size </u>
= ∑ order 1 + order 2 + ----- + order 10 ) / 10
= (47.55 + ...... + 58 ) / 10
= 478.8 / 10 = 47.88
Answer:
21/4 x 51/2 - k use the app Photomate if wrong
Answer:
According to Angle Bisector Theorem, if Ray YZ is an angle bisector, then MZ and NZ are congruent.
EH= 23. It is shown that ray FH bisects EFG, EF and EH are perpendicular, FG and HG are perpendicular. Then EH and GH are congruent. Therefore since GH= 23, then EH= 23
Answer:
142°
Step-by-step explanation:
