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GrogVix [38]
3 years ago
11

What is the volume of the rectangular prism, when the height is 10 1/2, the width is 2 3/4 and the base is 5?

Mathematics
1 answer:
Mademuasel [1]3 years ago
5 0
The formula for distinguishing the volume of a rectangular prism is the Base being multiplied by the Height. In other words, the formula is:
V = Bh

Now, we need to substitute our values for each variable to solve for our volume.
V = 5 x 10.5; multiply the two numbers.
V = 52.5.

Your answer for this is "C.) 52 1/2" (as "52.5" is equivalent to "52 1/2").

I hope this helps!
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when x = 0 y = 1
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2 years ago
Graph the image of △UVW after a reflection over the line y=-x
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Answer:

9514 1404 393

see attached

Step-by-step explanation:

Reflection over the line x = -1 alters the x-coordinates, but leaves the y-coordinates alone. The image point is as far horizontally from the reflection line as the pre-image point is. Each new x-coordinate is the old one subtracted from twice the x-value of the line of reflection: (x, y) ⇒ (-2-x, y) U(-8, -6) ⇒ U'(6, -6) V(-3, -6) ⇒ V'(1, -6) W(-4, -1) ⇒ W'(2, -1)

4 0
2 years ago
Read 2 more answers
Look at the formula for the volume of a cylinder below.
scZoUnD [109]
h = V / ( \pi r^2)

Okay, so we already have the volume equation for a cylinder here.
V = \pi r^2 h
Since we need to find the height(h), we need to basically isolate it in the equation. To do that we just have to divide both sides by (pi * r^2), where we end up with:
V / (\pi r^2) = h(\pi r^2) / (\pi r^2)
then
V / ( \pi  r^2) = h
h = V / ( \pi r^2)
8 0
2 years ago
Tissues of living organisms consist primarily of organic compounds; that is, they contain carbon molecules known as proteins, ca
Marianna [84]
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6 0
3 years ago
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A television game has 6 shows doors, of which the contests must pick 2. behind two of the doors are expensive cars, and behind t
Katyanochek1 [597]
The answer to this question:
One car probability 82/120
No car probability = 24/120
At least one car probability= 96/120

I will focus answering the 3 doors probability since the 2nd door problem is solved in the previous problem. (brainly.com/question/5761449)

No car condition
1. 1st door consolation, 2nd door consolation=, 3rd door consolation= 4/6 * 3/5 * 2/4= 24/120
This was also can be found by: (4!/1!)/ (6!/3!) = 24/120

(At least one car probability)  is the opposite of (no car probability) In this case, the easier way is 
100% - (no car probability) = 120/120 - 24/120= 96/120

One car probability is (At least one car probability) - (2 car probability). It will be easier to count the 2 car probability and subtract the (At least one car probability) 
Two car condition:
1. 1st door car, 2nd door car, 3rd door consolation = 2/6 * 1/5 * 4/4 =8/ 120
2.1st door car, 2nd door consolation, 3rd door car =2/6 * 4/5 * 1/4 = 8/120
3. 1st door consolation, 2nd door car, 3rd door car= 4/6 * 2/5 * 1/4= 8/120
The total probability will be 8/120+ 8/120 + /120= 24/120
This was also can be found by: (2!) (4!/2!)/ (6!/3!) = 24/120

One car probability =  (At least one car probability) - (2 car probability)= 96/120-24/120= 82/120
3 0
3 years ago
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