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Mama L [17]
3 years ago
6

Determine the factors of 5x2 + 6x − 8. (5x − 1)(x + 8) (5x − 8)(x + 1) (5x − 4)(x + 2) (5x − 2)(x + 4)

Mathematics
2 answers:
katrin2010 [14]3 years ago
8 0

Answer:

  (5x − 4)(x + 2)

Step-by-step explanation:

For the purpose, it is sufficient to make sure the middle terms match.

The middle term in the product of each of the answer choices is ...

  -1+40 ≠ 6

  -8+5 ≠ 6

  -4+10 = 6 . . . . . the third selection is the one you want

  -2+20 ≠ 6

Karo-lina-s [1.5K]3 years ago
5 0

Answer:  The correct option is (C) (5x − 4)(x + 2).

Step-by-step explanation:  We are given to determine the factors of the following quadratic expression :

E=5x^2+6x-8.

To factorize the given expression, we need to find two integers whose sum is 6 and whose product is -40.

The factorization is as follows :

E\\\\=5x^2+6x-8\\\\=5x^2+10x-4x-8\\\\=5x(x+2)-4(x+2)\\\\=(5x-4)(x+2).

Thus, the factors of the given expression are (5x - 4) and (x + 2). That is,

5x^2+6x-8=(5x-4)(x+2).

Option (C) is CORRECT.

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WILL GIVE A BRAINLESTTTT<br><br> What is the solution of 3x+8/x-4 &gt;= 0
Blababa [14]
Solution: (-Infinite, -8/3] U (4, Infinite)

Using that a fraction is greater than or equal to zero when the numerator and denominator have the same sign:
a/b>=0. Then we have two cases:
Case 1) If the numerator is positive, the denominator must be positive too (at the same time):
if a>=0 ∩ b>0

Or (U)

Case 2) If the numerator is negative, the denominator must be negative too (at the same time):
if a<=0 ∩ b<0

In this case a=3x+8 and b=x-4, then:

Case 1):
if 3x+8>=0 ∩ x-4>0
Solving for x:
3x+8-8>=0-8 ∩ x-4+4>0+4
3x>=-8 ∩ x>4
3x/3>=-8/3 ∩ x>4
x>=-8/3 ∩ x>4
Solution Case 1: x>4 = (4, Infinite)

Case 2):
if 3x+8<=0 ∩ x-4<0
Solving for x:
3x+8-8<=0-8 ∩ x-4+4<0+4
3x<=-8 ∩ x<4
3x/3<=-8/3 ∩ x<4
x<=-8/3 ∩ x<4
Solution Case 2: x<=-8/3 = (-Infinite, -8/3]

Solution= Solution Case 1 U Solution Case 2
Solution = (4, Infinite) U (-Infinite, -8/3]
Solution: (-Infinite, -8/3] U (4, Infinite)
7 0
3 years ago
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