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Mama L [17]
3 years ago
6

Determine the factors of 5x2 + 6x − 8. (5x − 1)(x + 8) (5x − 8)(x + 1) (5x − 4)(x + 2) (5x − 2)(x + 4)

Mathematics
2 answers:
katrin2010 [14]3 years ago
8 0

Answer:

  (5x − 4)(x + 2)

Step-by-step explanation:

For the purpose, it is sufficient to make sure the middle terms match.

The middle term in the product of each of the answer choices is ...

  -1+40 ≠ 6

  -8+5 ≠ 6

  -4+10 = 6 . . . . . the third selection is the one you want

  -2+20 ≠ 6

Karo-lina-s [1.5K]3 years ago
5 0

Answer:  The correct option is (C) (5x − 4)(x + 2).

Step-by-step explanation:  We are given to determine the factors of the following quadratic expression :

E=5x^2+6x-8.

To factorize the given expression, we need to find two integers whose sum is 6 and whose product is -40.

The factorization is as follows :

E\\\\=5x^2+6x-8\\\\=5x^2+10x-4x-8\\\\=5x(x+2)-4(x+2)\\\\=(5x-4)(x+2).

Thus, the factors of the given expression are (5x - 4) and (x + 2). That is,

5x^2+6x-8=(5x-4)(x+2).

Option (C) is CORRECT.

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Step-by-step explanation:

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3 0
3 years ago
Find the solutions of the quadratic equation 14x^2+9x+10=014x
Vesnalui [34]

Answer:

Option B. x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

14x^{2}+9x+10=0

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x=\frac{-9(+/-)\sqrt{-479}} {28}

Remember that

i=\sqrt{-1}

substitute

x=\frac{-9(+/-)\sqrt{479}i} {28}  

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5 0
3 years ago
I need to an explanation about this formula.
sergeinik [125]

I would answer but i can not see what it says.... Sorry


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3 years ago
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Paraphin [41]
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The sum of two values is added together. 

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~kaikers
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