Here's the solution ~
As we know, we can calculate the circumference of a circle in terms of its diameter as :
where, c = circumference and d = diameter
And also, circumference of circle is terms of radius (r) is :
Now, let's move on to questions ~
<h3>First </h3>
<h3 />
・ .━━━━━━━†━━━━━━━━━.・
<h3>Second</h3><h3 /><h3 /><h3 /><h3>
</h3>
・ .━━━━━━━†━━━━━━━━━.・
<h3>Third</h3>
・ .━━━━━━━†━━━━━━━━━.・
<h3>Fourth</h3>
・ .━━━━━━━†━━━━━━━━━.・
<h3>Fifth </h3>
・ .━━━━━━━†━━━━━━━━━.・
<h3>Sixth</h3>
➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
</u>
Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
Answer:
16
Step-by-step explanation:
The angle shown there is an example of a vertical angle. An opposite angle formed by intercecting lines. They are always congruent, so to solve this, you must set them equal to eachother. you can gather the equation 4x-5=59. From there, you just solve it like you would any two step equation.
It is $100 because if you work it out on paper then you could have on the paper and the answer is 100$
Hello,
if p is false then ~p is true
if q is false then ~q is true
if ~p is true and ~q is true then <u>~q and ~p is true</u>