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saul85 [17]
2 years ago
14

Somebody help me i will mark you has brainlist

Mathematics
1 answer:
Serggg [28]2 years ago
3 0

Answer:

Salt

Step-by-step explanation:

At its peak, Ghana was chiefly bartering gold, ivory, and slaves for salt from Arabs and horses, cloth, swords, and books from North Africans and Europeans. As salt was worth its weight in gold, and gold was so abundant in the kingdom, Ghana achieved much of its wealth through trade with the Arabs.

Hope this helps!

Brain-List?

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Factorise each of the following<br> a2+9a+8
Tanzania [10]

Answer:

Step-by-step explanation:

I suppose the expression is this a^2+9a+8.

We can factor out this expression ( Remember, find two numbers that the sum is 9 and the product is 8. The numbers are 8 and 1)

a^2+9a+8=(a+1)(a+8)

8 0
2 years ago
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HELP QUICK! You must find all intervals<br> where f(x) is negative. <br> f(x)=2(x+3)(x-7)
beks73 [17]

Answer:

any # where -2<=x<7

Step-by-step explanation:

(x-7) would be negative and (x+3) positive, resulting in f(x) being negative.

4 0
2 years ago
4(y+8)=100 help me pls due today
Otrada [13]

Answer:

y=17

Step-by-step explanation:4(y+8)=100

We move all terms to the left:

4(y+8)-(100)=0

We multiply parentheses

4y+32-100=0

We add all the numbers together, and all the variables

4y-68=0

We move all terms containing y to the left, all other terms to the right

4y=68

y=68/4

y=17

   

8 0
2 years ago
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Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)
GarryVolchara [31]

<u>Question 6</u>

1) \overline{AB} \cong \overline{BD}, \overline{CD} \perp \overline{BD}, O is the midpoint of \overline{BD}, \overline{AB} \cong \overline{CD} (given)

2) \angle ABO, \angle ODC are right angles (perpendicular lines form right angles)

3) \triangle ABO, \triangle CDO are right triangles (a triangle with a right angle is a right triangle)

4) \overline{BO} \cong \overline{OD} (a midpoint splits a segment into two congruent parts)

5) \triangle ABO \cong \triangle CDO (LL)

<u>Question 7</u>

1) \angle ADC, \angle BDC are right angles), \overline{AD} \cong \overline{BD}

2) \overline{CD} \cong \overline{CD} (reflexive property)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \triangle ADC \cong \triangle BDC (LL)

5) \overline{AC} \cong \overline{BC} (CPCTC)

<u>Question 8</u>

1) \overline{CD} \perp \overline{AB}, point D bisects \overline{AB} (given)

2) \angle CDA, \angle CDB are right angles (perpendicular lines form right angles)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \overline{AD} \cong \overline{DB} (definition of a bisector)

5) \overline{CD} \cong \overline{CD} (reflexive property)

6)  \triangle ADC \cong \triangle BDC (LL)

7) \angle ACD \cong \angle BCD (CPCTC)

8 0
2 years ago
Show work please!!!!! HELPPPP
scoundrel [369]
If you would like to find the volume here:

L•W•H

Big Rectangular: 10•14•6
Small Rectangular: 1•2•3


Surface Area:

2(L•W) + 2(L•H) + 2(W•H)

Big Rectangular: 2(10•14) + 2(10•6) + 2(14•6)
Small Rectangular: 2(1•2) + 2(1•3) + 2(2•3)
7 0
2 years ago
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