Short Answerx1 = 4.8284
x2 = - 0.828
RemarkSubstitute the value for y from the first equation into the second equation. Multiply by 4 and then see if it factors out. Solve for x first and then y.
Step one Solve for y in the first equation. Subtract x from both sides.
y = 2 - x
Step TwoEquate the two ys.
2 - x = - 1/4x^2 + 3
Step ThreeBring the left side over to the right side.
0 = -1/4 x^2 + x + 3 - 2 Combine the like terms.
0 = -1/4 x^2 + x + 1
Step Four0 = -1/4 x^2 + x + 1 Multiply through by 4
0 = - x^2 + 4x + 4
Step fiveThis won't factor. The only thing you can do is use the quadratic equation for roots.
a = - 1
b = 4
c = 4
x = 2 +/- sqrt(4^2 * 2) / (- 2)
x = 2 +/- 4 sqrt(2) / - 2
x = 2 -/+ 2 sqrt(2)
x = 2 -/+ 2 *(1.414)
x = 2 -/+ 2.828
x1 = 4.8284
x2 = - 0.828
If Mike has half as many games as Paul, then multiply 6 * 2 to get the number of games that Paul has.
6 * 2 = 12
Paul has 12 games.
Answer:
(-2x^4y^2)^3
the solution is -8x^12y^6
Step-by-step explanation:
Actually in this case we will make use of the z test
statistic. In which we calculate for the z score and then use the standard
normal distribution tables to find for the P value at the calculate z score.
z = (x – u) / s
z = (97 – 98) / 2
z = -0.5
The z value should be greater than 1.65 to for the null
hypothesis to be accepted. Hence rejected.