Answer:
Each month is equally likely
Step-by-step explanation:
Given that for a recent year, the following are the numbers of homicides that occurred each month in New York City: 
38, 30, 46, 40, 46, 49, 47, 50, 50, 42, 37, 37.
We have to check whether it is equally likely for each of the 12 months
Set Hypotheses as
H0: All months are equally likely
Ha: atleast two months are not equally likely
(Two tailed chisquare test at 5% significance level)
This is a test for chi square goodness of fit and so assuming H0 to be true
we divide the total equaly among 12 months as expected
               Observed	Expected  Chi square
Jan                    38     42.66666667  0.510416667
Feb                    30     42.66666667  3.760416667
Mar                    46     42.66666667  0.260416667
Apr                   40    42.66666667  0.166666667
May                   46    42.66666667  0.260416667
June           49    42.66666667  0.940104167
July                   47    42.66666667  0.440104167
Aug                  50    42.66666667  1.260416667
Sep                  50    42.66666667  1.260416667
Oct                  42    42.66666667  0.010416667
Nov                  37    42.66666667  0.752604167
Dec                  37    42.66666667  0.752604167
Total        512     512                 10.375
df=11
p value = 0.497
Since p >0.05 our alpha we accept H0
Each month is equally likely