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3 years ago

What is the equation of the following line? Be sure to scroll down first to see all answer options.

Mathematics

1 answer:

Yuri [45]3 years ago

3 0

Answer:

D: y=6x

Step-by-step explanation:

y=mx+b

b=0

y=mx

-3=m * (-1/2)

m=6

y=6x

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Annie is adding the expression 4 + 5 + (–4) and follows the procedure of starting at 4, moving right 5 units, and then moving le

jekas [21]

Answer:

Step-by-step explanation:

hello

4 0

3 years ago

We roll two fair 6-sided dice. Each of the 36 possible outcomes is assumed to be equally likely. (a) Given that the roll results

boyakko [2]

Answer:

a) $\frac{1}{7}$

b) $\frac{2}{15}$

Step-by-step explanation:

Given : We roll two fair 6-sided dice. Each of the 36 possible outcomes is assumed to be equally likely.

The outcomes are :

(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

(a) Given that the roll results in a sum of 3 or more, find the conditional probability that doubles (the first and the second rolls result in the same number) are rolled.

Let P(A) be the probability of event that the roll results in a sum of 3 or more.

Except (1,1) rest sum is 3 or greater than 3.

So, $P(A)=\frac{35}{36}$

Now, P(A and B) is that the roll results in a sum of 3 or more and that doubles (the first and the second rolls result in the same number) are rolled.

i.e. (2,2), (3,3), (4,4), (5,5), (6,6) - 5

$P(A\cap B)=\frac{5}{36}$

The conditional probability is given by,

$P(B|A)=\frac{P(A\cap B)}{P(A)}$

$P(B|A)=\frac{\frac{5}{36}}{\frac{35}{36}}$

$P(B|A)=\frac{5}{35}$

$P(B|A)=\frac{1}{7}$

(b) Given that the two dice land on different numbers, find the conditional probability that the sum is 5.

Let P(A) be the probability of event that two dice land on different numbers.

Except (1,1),(2,2), (3,3), (4,4), (5,5), (6,6) rest two dice land on different numbers.

So, $P(A)=\frac{30}{36}$

Now, P(A and B) is that two dice land on different numbers and the sum is 5.

i.e. (1,4), (2,3), (3,2), (4,1) - 4

$P(A\cap B)=\frac{4}{36}$

The conditional probability is given by,

$P(B|A)=\frac{P(A\cap B)}{P(A)}$

$P(B|A)=\frac{\frac{4}{36}}{\frac{30}{36}}$

$P(B|A)=\frac{4}{30}$

$P(B|A)=\frac{2}{15}$

4 0

3 years ago

The sum of three times a number, x, and 12 (pre-algebra)

Mamont248 [21]

the pre algebra is 17 and it is also 12

5 0

2 years ago

Read 2 more answers

Can someone help me please?

stira [4]

Answer:

500000

Step-by-step explanation:

We need to find the value of the given expression :

$5^{\dfrac{5}{2}}\times 20^{\dfrac{3}{2}}\div 10^{-2}$

We can do it as per BODMAS rule.

$5^{\dfrac{5}{2}}\times (\dfrac{20^{\dfrac{3}{2}}}{10^{-2}})\\\\=5^{\dfrac{5}{2}}\times {20^{\dfrac{3}{2}}}\times {10^{2}}\\\\=5^{\dfrac{5}{2}}\times {20^{\dfrac{3}{2}}}\times 100\\\\=5^{\dfrac{5}{2}}\times {(5\times 4)^{\dfrac{3}{2}}}\times 100\\\\=5^{\dfrac{5}{2}}\times {(5^{\dfrac{3}{2}})\times (4)^{\dfrac{3}{2}}}\times 100\\\\=5^{(\dfrac{5}{2}+\dfrac{3}{2})}\times 2^2^{\dfrac{3}{2}}\times 100\\\\=5^4\times 2^3\times 100\\\\=625\times 8\times 100\\\\=500000$

So, the required answer is 500000.

7 0

2 years ago

a cylinder water tank carries a volume of 150L when it is full. The water tank has a base surface with a diameter of 140 cm. wha

REY [17]

Answer:

9.74418019cm=h

~ 9.7442

Step-by-step explanation:

volume of a cylinder=πr²h

radius=½of diameter

=½×140cm

=70cm

1l=1000cm³

150l=150l/1l×1000cm³

=150000cm³

150000cm³=π(70cm)²×h

150000cm³=15393.8040cm²h

150000cm³/15393.8040cm²=15393.8040cm²h/15393.8040cm²

150000cm³/15393.8040cm²=h

9.74418019cm=h

7 0

3 years ago