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Anton [14]
4 years ago
10

Find the discriminant and determine the nature of the roots to the quadratic equation

Mathematics
1 answer:
Katen [24]4 years ago
3 0
№17
x^{2} +6x-7=0 \\ D=6 ^{2} -4*(-7)=36+28=64=8 ^{2}  \\  \\  x_{1} = \frac{-6+8}{2} =1 \\  \\  x_{2} = \frac{-6-8}{2} =-7
Answer: x₁ = 1
               x₂ = - 7

№18
2 x^{2} -3x+4=3 \\ 2 x^{2} -3x+4-3=0 \\ 2 x^{2} -3x+1=0 \\  \\ D= -3 ^{2} -4*2=9-8=1 \\  \\  x_{1} = \frac{3+1}{2*2} = \frac{4}{4} =1 \\  \\  x_{2} = \frac{3-1}{2*2} = \frac{2}{4} =0.5
Answer: x₁ = 1
               x₂ = 0,5.

№19
2 x^{2} -4x-5=0 \\  D=-4 ^{2} -4*2*(-5)=16+40=56 \\  \\  x_{1}= \frac{4+ \sqrt{56} }{2*2}  = \frac{4}{4} + \sqrt{ \frac{56}{16} } =1+ \sqrt{3.5}  \\  \\  x_{2} = \frac{4- \sqrt{56} }{2*2} = \frac{4}{4} -  \sqrt{ \frac{56}{16} } =1- \sqrt{3.5} 

Answer: x₁ = 1 + √3.5
               x₂ = 1 - √3.5

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