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USPshnik [31]
4 years ago
15

The probability that a train leaves on time is 0.9. The probability that the train arrives on time and leaves on time is 0.36. W

hat is the probability that the train arrives on time, given that it leaves on time?
0.4
0.9
0.27
0.36
Mathematics
2 answers:
ASHA 777 [7]4 years ago
5 0
P(arrives on time given leaves on time)=
P(B | A)= P(B n A) / P(A)
= P(A n B) / P(A)
= 0.36 / 0.9
= 0.4
Roman55 [17]4 years ago
4 0

.4 is the answer .4 is the answer .4 is the answer .4 is the answer .4 is the answer .4 is the answer .4 is the answer .4 is the answer .4 is the answer .4 is the answer

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Answer:

answer B: (2,-2)

Step-by-step explanation:

First, write the equations on top of each other:

3x+2y=2\\2x-y=6

Then, multiply the the second equation by 2 so that we can use elimination of the y-variable:

3x+2y=2\\2(2x-y)=2(6)\\\\3x+2y=2\\4x-2y=12

Next, use elimination to find the value of "x":

3x+2y=2\\+(4x-2y=12)\\\\7x+0=14\\7x=14\\\frac{7x}{7}=\frac{14}{7}\\x=2

So, your x-value is 2.

Now, substitute your x-value into one of your equations, let's take the second equation, 2x-y=6:

2x-y=6\\2(2)-y=6\\4-y=6\\4-4-y=6-4\\-y=2\\\frac{-y}{1}=\frac{2}{-1}\\y=-2

Your y-value is -2.

With all your information gathered, you find that the solution to this system of equation is (2,-2).

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