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UNO [17]
3 years ago
15

The mean incubation time of fertilized eggs is 19 days. Suppose the incubation times are approximately normally distributed with

a standard deviation of 1 day. Answer the following. For each question draw an appropriate distribution function​ (graph) to represent the​ data, shade the desired area, and show all​ work, including what you input into your calculator to attain your results.
(A) The 14th percentile for incubation times is __ days.
(B) The incubation times that make up the middle 97% of fertilized eggs are __ to __ days.
Mathematics
1 answer:
pochemuha3 years ago
8 0

Answer:

a)17.92

b) 16.83 .... 21.17

Step-by-step explanation:

ρ→   z

0.14 = -1.080319341

-1.080 = (x - 19)/1 = 17.92

~~~~~~~~~~~~~~~~~~

3% / 2 = 1.5%

1.5% - 98.5%

ρ→   z

0.015 = -2.170090378 ....  -2.17 = (x-19) =16.83

0.985 = 2.170090378  ....   2.17 = (x-19) =21.17

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PLEASE HELP ASAP!!! Will give brainliest!
elena-s [515]

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1,000,000 / 100 = 10,000

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7 0
3 years ago
12.6 + 4m = 9.6 + 8m
Sergeu [11.5K]

Answer:

3 = 4m or  0.75 = m

Step-by-step explanation:

12.6 + 4m = 9.6 + 8m

Subtract 4m from both sides of the equation

12.6 = 9.6 + 4m

Subtract 9.6 from both sides of the equation

3 = 4m

Divide by four on both sides of the equation

0.75 = m

I Hope That This Helps! :)

7 0
3 years ago
Read 2 more answers
Find the distance between xequals[Start 2 By 1 Matrix 1st Row 1st Column 8 2nd Row 1st Column negative 5 EndMatrix ]and yequals[
kherson [118]

Answer:

Distance =√(x₁ - y₁)²+ (x₂ - y₂)² = √97 = 9.85

Step-by-step explanation:

The Matrix X and Y could also be referred to as vectors in Rⁿ dimensions.

if Vector X = ( x₁ , x₂)   and  Vector  Y = (y₁ , y₂)

then, Distance (X-Y) = ||X-Y|| = √(x₁ - y₁)²+ (x₂ - y₂)²

where, x₁ = 8, x₂ = -5   and  y₁ = -1 , y₂ = -9

Distance = √(8 - (-1))²+ (-5 - (-9))² = √9² + 4² =√97 = 9.85

4 0
3 years ago
Hello, who would you do me the favor of helping me with this question?
Fed [463]

Step-by-step explanation:

diagonal of a polygon formular =sum of diagonal =5-3-5/2. A triangle do not have diagonal

4 0
3 years ago
3/4 x 3 2/5 - 5/5(find the value of each of the following) ​
Triss [41]

The value of the given expression is \frac{-13}{20}.

Solution:

Given expression is \frac{3}{4} \times3\frac{2}{5}-\frac{5}{5}.

Let us first convert mixed fraction into improper fraction.

3\frac{2}{5}=\frac{(3\times5)+2}{5}=\frac{17}{5}

Substitute this in the given expression.

\frac{3}{4} \times3\frac{2}{5}-\frac{5}{5}=\frac{3}{4} \times\frac{7}{15}-\frac{5}{5}

                  =\frac{21}{60}-\frac{5}{5}

To simplify the above expression, 21 and 60 are cancelled by 3.

                 =\frac{7}{20}-\frac{1}{1}

Do cross multiplication to make the denominator same.

                 =\frac{7}{20}-\frac{20}{20}

                 =\frac{7-20}{20}

                 =\frac{-13}{20}

The value of the given expression is \frac{-13}{20}.

7 0
3 years ago
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