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2 years ago

A restaurant advertises 256 types of nachos. how many topping ingredients must be available

1 answer:

3 0

Well, this depends on the number of topping ingredients you have for each serving of nachos. The general solution will be simply to add all the topping ingredients for each type. Assuming there is an average of 7 topping ingredients for every type, namely: cheese, fried beans, sour cream, onions, jalapeños, salsa, and guacamole. Hence,

Topping Ingredients = 7*256 = 1,792

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Jaime bikes 5 1/4 miles on Monday 6 7/8 miles on Tuesday and 8 1/2 miles on Wednesday if he continue the pattern how many miles

Shtirlitz [24]

11 2/8 there is a 1 5/8 between each of them so you keep adding 1 5/8 miles each day.

8 0

3 years ago

Natasha ran 3.1 kilometers. Tonya ran 4 meters more than half as far as Natasha. How many meters did Tonya run?

Levart [38]

The answer would be idk
So it 5.6

4 0

2 years ago

Calculate (a) the total installment price, (b) the carrying charges, and (c) the number of months needed to save the money at th

Paraphin [41]

8.50 + 11 (24) = 272.50
The total price
Carrying charges 72.50

divide $11 into 200

6 0

2 years ago

Read 2 more answers

8. Number of boys in a class is twice the number of girls. 20% of the girls are brunettes and of the rest – half are blondes: Ma

slega [8]

Answer:

20 boys

Step-by-step explanation:

b = 2g

100% - 20% = 80%

80% ÷ 2 = 40% = 0.4

0.4g = 4 ⇒ g = 4 ÷ 0.4 = 10

b = 2 × 10 = 20

There are 10girls and 20 boys study in the class.

8 0

2 years ago

The following describes a sample. The information given includes the five number summary, the sample size, and the largest and s

lys-0071 [83]

Answer:

$L= Q_1 - 1.5*IQR = 210 -1.5*40 =150$

$U= Q_3 + 1.5*IQR = 250 +1.5*40 =310$

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

Step-by-step explanation:

For this case we have the 5 number summary

(160,210,220,250,270)

So then we have:

minimum = 160 , Q1 = 210, Q2= Median=220, Q3 = 250, Max=270

If we find the interquartile range we got:

$IQR = Q_3 -Q_1 = 250-210 =40$

For this case we need to find the lower and upper limit with the following formulas:

$L= Q_1 - 1.5*IQR = 210 -1.5*40 =150$

$U= Q_3 + 1.5*IQR = 250 +1.5*40 =310$

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

4 0

3 years ago