First figure out how much it costs to rent seven movies a month. f(7)=2(7) + 12–> 14 + 12–> $26 Now we need to find the difference between 26 and 10. 26 - 10= 16. So Casey needs $16 more to rent 7 movies a month
Answer:
C.) 87
Step-by-step explanation:
if you look at it from the other side, its counting down from 91 from the left.
To be honest, these answer choices are a bit baffling. The best answer in my opinion would be to do at least two of the three options given below.
- Place a price floor above the equilibrium.
- Decrease imports from other countries.
- Reduce current supply (reduce herd sizes).
Doing that should increase the prices.
Placing a floor above equilibrium will force the equilibrium to move upward, and with the reduce in supply from other countries, demand will shift toward the domestic producers. Without the demand shift, there simply would be an oversupply or surplus of dairy. Either the surplus is thrown away or its simply housed somewhere else (often at taxpayer expense).
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If you place a ceiling below equilibrium, then the price will go down to that ceiling value. That will be the highest price possible. This is the opposite of what the farmers want. It gets even worse when you increase milk imports (since supply goes up leading to further reduced prices). So that rules out choice A.
If you place a ceiling above equilibrium, then nothing happens. The price stays at equilibrium. Nothing too exciting here. This rules out choice B (though I agree with the "decrease imports" portion).
If you set a floor below equilibrium, then nothing happens similar to the last paragraph above. The price stays where it is. We can rule out choice C. Reducing herd sizes will reduce supply so that could maybe increase prices.
I'm not really familiar with the term "arbitrage" so I probably won't be any help here. That seems like an answer choice that is a distraction, but I'm not sure.
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Answer:
C, A, A
Step-by-step explanation:
In general, you ...
- identify the coefficients of one of the variables
- swap them, and negate one of them
- multiply the corresponding equations by the "adjusted" coefficients.
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In problem 1, the x-coefficients are 8 and 2. A common factor of 2 can be removed so that we're dealing with the numbers 4 and 1. Assuming we want to multiply one of the equations by 1, leaving it unchanged, the value we want to multiply by will be -4. After we swap the coefficients, that multiplier is associated with equation 2:
multiply equation 2 by -4 . . . (eliminates x)
Likewise, the y-coefficients in problem 1 are -1 and 3. Again, if we want to multiply one of the equations by 1, leaving it unchanged, the coefficient we will change the sign of is -1 (becomes 1). After we swap the coefficients, the multiplier 3 is associated with equation 1:
multiply equation 1 by 3 . . . (eliminates y)
These two choices are B and A, respectively, so the one that does NOT work for problem 1 is choice C, as indicated below.
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The other problems are worked in a similar fashion.
