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DENIUS [597]
3 years ago
12

Determine whether each set of side lengths could be the sides of a right triangle.

Mathematics
1 answer:
garri49 [273]3 years ago
7 0
It is 10.5cm, 20.8cm, 23.3cm
as (10.5)^2 + (20.8)^2 = 542.89 { pythagorus theorem}
and (23.3)^2 = 542.89

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HELP
Lostsunrise [7]

Answer:

A.

{b}^{2}  + 3b - 3 = 0

Step-by-step explanation:

{b}^{2}  + 3b - 3 = 0 \\ because \:  \:  {b}^{2}  < 4ac \\ {b}^{2}    = {3}^{2}  = 9 \\ 4ac = 4 \times 1 \times  - 3 =  - 12 \\ hence :  {b}^{2}  < 4ac

3 0
2 years ago
Convert to standard form: F(x) = 2x + 4
mote1985 [20]
The answer will be F=2x/x + 4/x
7 0
3 years ago
Select the scenario that best matches the equation below:<br><br> 2x + 5 = 25
son4ous [18]

Answer:

Jamie has 5 cards. his friend Bill gives him twice the number of cards he has. After this Jamie has 25 card total. I hope that this helps!!

7 0
2 years ago
A jeweler wants to make 14 grams of an alloy that is precisely 75% gold.. The jeweler has alloys that are 25% gold, 50% gold, &a
Goryan [66]

Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.

As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.

One alloy is 82% gold and, the second can be chosen between 25% gold, 50% gold, so there are two cases.

Case 1: 82% gold + 50% gold

Let x grams of 82% gold and y  grams of 50% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 50% of y

\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times y \\\\

\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times (14-x)  [as x+y=14]

\Rightarrow 75 \times 14 = 82 \times x + 50 \times (14-x)  \\\\\Rightarrow 75 \times 14 = 82 \times x + 50 \times14-50\times x \\\\\Rightarrow 75 \times 14 = 32 \times x + 50 \times14 \\\\\Rightarrow 32 \times x =75 \times 14 - 50 \times14 \\\\

\Rightarrow x =(25 \times 14)/32=10.9375 grams

and y = 14-x= 14-10.9375=3.0625 grams.

Hence, 10.9375 grams of 82% gold and 3.0625  grams of 50% gold added to make 14 grams of 75% gold.

Case 2: 82% gold + 25% gold

Let x grams of 82% gold and y  grams of 25% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 25% of y

\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times y \\\\\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times (14-x) \\\\ \Rightarrow 75 \times 14 = 82 \times x + 25 \times (14-x)  \\\\\Rightarrow 75 \times 14 = 82 \times x + 25 \times14-25\times x \\\\\Rightarrow 75 \times 14 = 57 \times x + 25 \times14 \\\\\Rightarrow 57 \times x =75 \times 14 - 25 \times14 \\\\

\Rightarrow x =(50 \times 14)/57=12.28 grams

and y = 14-x= 14-12.28=1.72 grams.

Hence, 12.28 grams of 82% gold and 1.72  grams of 50% gold added to make 14 grams of 75% gold.

3 0
2 years ago
On a piece of paper graph the system of equations. Then determine which answer choice matches the graph you drew and identify th
PSYCHO15rus [73]

Answer:

I think you meant for the plus sign in the second problem to be an = sign so the equation looks like this y=-x+4

If so your answer is A the first graph

I graphed it on desmos calculator


6 0
3 years ago
Read 2 more answers
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