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GarryVolchara [31]
3 years ago
10

PLEASE HELP ILL GIVE 77 POINTS!!!!!!!!!!!!

Mathematics
1 answer:
Vikki [24]3 years ago
8 0

Answer:

i think its twelve nine and five

Step-by-step explanation:

not one hundred percent sure

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The equations : -3x+4y=-30− and 9x + 5 y = 39 intersect at the coordinate (h, k). What is the value of h?
Phantasy [73]

Answer:

h = 6

Step-by-step explanation:

Given the 2 equations

- 3x + 4y = - 30 → (1)

9x + 5y = 39 → (2)

We require the value of the x- coordinate at the point of intersection, thus require to eliminate the y- term from the equations

Multiply (1) by 5 and (2) by - 4

- 15x + 20y = - 150 → (3)

- 36x - 20y = - 156 → (4)

Add (3) and (4) term by term thus eliminating y

- 51x = - 306 ( divide both sides by - 51 )

x = h = 6

5 0
3 years ago
X/3-4=-7<br><br> please help me solve
Vanyuwa [196]
In order to solve this we need to get x by itself on one side.

We need o start by adding across the 4 so that we get:

x/3 = -7 + 4 = -3

We then need to multiply both sides by 3 to get a singular x:

x = -3 * 3 = -9
5 0
3 years ago
Read 2 more answers
Half of a set of the parts are manufactured by machine A and half by machine B. Ten percent of all the parts are defective. Six
baherus [9]

Answer:

The probability that a part was manufactured on machine A is 0.3

Step-by-step explanation:

Consider the provided information.

It is given that Half of a set of parts are manufactured by machine A and half by machine B.  

P(A)=0.5

Let d represents the probability that part is defective.

Ten percent of all the parts are defective.

P(d) = 0.10

Six percent of the parts manufactured on machine A are defective.

P(d|A)=0.06

Now we need to find the probability that a part was manufactured on machine A, and given that the part is defective :

P(A|d) =\frac{P(A \cap d)}{P(d)}

P(A|d) =\frac{P(d|A)\times P(A)}{P(d)}\\P(A|d)= \frac{0.06\times 0.5}{0.10}

P(A|d)= 0.3

Hence, the probability that a part was manufactured on machine A is 0.3

8 0
3 years ago
Use the drop-down menus to complete the proof. Given that w ∥ x and y is a transversal, we know that ∠1 ≅∠5 by the . Therefore,
ololo11 [35]

Answer:

From the graph attached, we know that \angle 1 \cong \angle 5 by the corresponding angle theorem, this theorem is about all angles that derive form the intersection of one transversal line with a pair of parallels. Specifically, corresponding angles are those which are placed at the same side of the transversal, one interior to parallels, one exterior to parallels, like \angle 1 and \angle 5.

We also know that, by definition of linear pair postulate, \angle 3 and \angle 1 are linear pair. Linear pair postulate is a math concept that defines two angles that are adjacent and for a straight angle, which is equal to 180°.

They are supplementary by the definition of supplementary angles. This definition states that angles which sum 180° are supplementary, and we found that \angle 3 and \angle 1 together are 180°, because they are on a straight angle. That is, m \angle 3 + m \angle 1 = 180\°

If we substitute \angle 5 for \angle 1, we have m \angle 3 + m \angle 5 = 180\°, which means that \angle 3 and \angle 5 are also supplementary by definition.

4 0
3 years ago
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The sides of an equilateral triangle measure 16 inches. The midpoints of the sides of the triangle are joined to form another eq
Alex Ar [27]

Answer:

  90 inches

Step-by-step explanation:

The perimeter of the inscribed triangle is 1/2 that of the enclosing triangle. So, the total of perimeters is ...

  (3·16 in)(1 +1/2 +1/4 +1/8) = (48 in)(15/8) = 90 inches

5 0
3 years ago
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