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3 years ago

PLEASE HELP ILL GIVE 77 POINTS!!!!!!!!!!!!

Mathematics

1 answer:

Vikki [24]3 years ago

8 0

Answer:

i think its twelve nine and five

Step-by-step explanation:

not one hundred percent sure

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a collector has 120 movie posters and 100 band posters she wants to sell 24 movie posters but still have her poster collection m

sukhopar [10]

Twenty band posters should be sold

5 0

3 years ago

a random sample of high school seniors were asked whether they were applying for college. the resulting confidence interval for

Artist 52 [7]

Using the confidence interval, the margin of error is 0.02.

In the given equation we have to find the margin of error.

The resulting confidence interval for the proportion of students applying for college is (0.65,0.69).

Let p = population proportion of students applying for college

P = Sample proportion of students applying for college

ME = margin of error

So the confidence interval

CI = (P-ME, P+ME)

From the given question;

(P-ME, P+ME) = (0.65,0.69)

So lower bound= P-ME = 0.65............................(1)

Upper Bound = P+ME = 0.69............................(2)

Simplifying the Equation 1 and 2

Add equation 1 and 2 we get

2P = 1.34

Divide by 2 on both side we get

P = 0.67

Putting the value of P in the equation 2

P+ME = 0.69

0.67+ME=0.69

Subtract 0.67 on both side we get

ME = 0.02

Hence, the margin of error is 0.02.

To learn more about margin of error link is here

brainly.com/question/10501147

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3 0

1 year ago

Select the correct answer.

Iteru [2.4K]

Answer A

They have the same x-intercept but different end behavior as x approaches ∞ :)

4 0

2 years ago

ASAP PLEASE ANSWER

pickupchik [31]

Answer:

Step-by-step explanation:

Hope this helps!

7 0

3 years ago

Ginger buys lunch at school every day. She always gets

shepuryov [24]

Answer:

The estimated probability that Ginger will eat a a pizza everyday of the week is;

D. 8/10 = 80%

Step-by-step explanation:

The given parameters are;

The frequency with which Ginger buys launch = Everyday

The percentage of the time the cafeteria has pizza out = 80%

The outcome of 0 and 1 = No pizza available

The outcome of 2, 3, 4, 5, 6, 7, 8, and 9 = Pizza available

Therefore, we have the;

Group number ${}$ Percentage of time pizza available

1 ${}$ 80%

2 ${}$ 80%

3 ${}$ 80%

4 ${}$ 80%

5 ${}$ 40%

6 ${}$ 100%

7 ${}$ 80%

8 ${}$ 100%

9 ${}$ 80%

10 ${}$ 80%

Therefore, the sum of the percentages outcome the days Ginger eats pizza = 0.8 + 0.8 + 0.8 + 0.8 + 0.4 + 1 + 0.8 + 1 + 0.8 + 0.8 = 8

The number of runs of simulation = 10 runs

The estimated probability that Ginger will eat a a pizza everyday of the week = (The sum of the percentages outcome the days Ginger eats pizza)/(The number of runs of simulation)

∴ The estimated probability that Ginger will eat a a pizza everyday of the week = 8/10

6 0

3 years ago

Read 2 more answers