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IgorC [24]
2 years ago
11

What are true bearings and how can they be calculated/read?

Mathematics
2 answers:
True [87]2 years ago
8 0
I was going to right the same as the guy above
lubasha [3.4K]2 years ago
3 0

Answer:

Compass bearings use the four directions on a compass in order to find the direction of one object from another. An example is N20°E. True bearings use the number of degrees measured clockwise from north an object is. An Example is 120°T.

Compass bearings use the four directions on a compass in order to find the direction of one object from another. An example is N20°E. True bearings use the number of degrees measured clockwise from north an object is. An Example is 120°T.

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Rachel received a $80 gift card for a coffee store. She used it in buying some coffee that cost $7.61 per pound. After buying th
Olin [163]

Answer:

6

Step-by-step explanation:

80- 34.34 = 45.66

45.66 ÷ 7.61 = 6

5 0
3 years ago
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a(t) = (t - k)(t - 3)(t - 6)(t + 3) is a polynomial function of t, where k is a constant. Given that a(2) = 0, what is the absol
koban [17]
If a(2) = 0, then k=2. The product of the zeros is
(2)*(3)*(6)*(-3) = -108

The absolute value of the product of zeros of a(t) is 108.
4 0
3 years ago
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Please help me please
photoshop1234 [79]

Answer:

(-6,0), (-5,-1), and (-1,-2)

-Please mark as brainliest!-

-Hope this helps!-

-Good luck!-

Step-by-step explanation:

0+3(-3) greater than or equal to -8

-9 greater than or equal to -8

No

-16+3(2) greater than or equal to -8

-10 greater than or equal to -8

No

-6+3(0) greater than or equal to -8

-6 greater than or equal to -8

Yes

-5+3(-1) greater than or equal to -8

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6 0
3 years ago
what is the simplified form of the following expression? Assume X 0 and y 0. 2(^4 sqrt 16 x) -2(^4 sqrt 2y )+3 (^4 sqrt 81x ) -4
eduard

For this case we have the following expression:

2(\sqrt[4]{16x})-2(\sqrt[4]{2y})+3(\sqrt[4]{81x})-4(\sqrt[4]{32y})

Rewriting the numbers within the roots we have:

2(\sqrt[4]{2*2*2*2x})-2(\sqrt[4]{2y})+3(\sqrt[4]{3*3*3*3x})-4(\sqrt[4]{2*2*2*2*2y})

Then, by properties of powers we have:

2(\sqrt[4]{2^4x})-2(\sqrt[4]{2y})+3(\sqrt[4]{3^4x})-4(\sqrt[4]{2^42y})

Then, by radical properties we have:

2(2\sqrt[4]{x})-2(\sqrt[4]{2y})+3(3\sqrt[4]{x})-4(2\sqrt[4]{2y})

Rewriting the expression we have:

4\sqrt[4]{x}-2\sqrt[4]{2y}+9\sqrt[4]{x}-8\sqrt[4]{2y}

Finally, adding similar terms we have:

(4+9)\sqrt[4]{x}-(2+8)\sqrt[4]{2y}

13\sqrt[4]{x}-10\sqrt[4]{2y}

Answer:

The simplified form of the expression is:

13\sqrt[4]{x}-10\sqrt[4]{2y}

7 0
3 years ago
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I’ll really appreciate it if you help me out on this one , im currently failing this class please help
Arisa [49]
This is infinity solutions -
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