A triangle has sides with the following lengths: AB=3, BC=4, CA=5

antoniya [11.8K]

ANSWER

1

EXPLANATION

We want to find the value of:

$3^0$

One of the rules of Indices, called the Power with Exponent Zero rule, states that any number raised to the power of zero is equal to 1.

This means that:

$3^0\text{ = 1}$

That is the answer.

7 0

1 year ago

If a coin has been altered so that the probability of heads coming up is 3/10, then the probability of tails coming up is also 3

Vadim26 [7]

False. Since the probability of one side of the coin is 3/10, the other must be 7/10.

6 0

3 years ago

Read 2 more answers

Which shows the correct way to use the rule ""multiply by the reciprocal"" for the expression below? 7 divided by StartFraction

guajiro [1.7K]

Given:

The expression is $\dfrac{7}{\frac{5}{8}}$ .

To find:

The shows the correct way to use the rule ""multiply by the reciprocal"" for the given expression.

Solution:

According to the rule "multiply by the reciprocal", if a,b,c,d are four number, then

$\dfrac{\dfrac{a}{b}}{\dfrac{c}{d}}=\dfrac{a}{b}\times \dfrac{d}{c}$

We have,

$\dfrac{7}{\frac{5}{8}}$

It can be written as

$\dfrac{7}{\frac{5}{8}}=\dfrac{\dfrac{7}{1}}{\dfrac{5}{8}}$

Using the rule "multiply by the reciprocal", we get

$\dfrac{\dfrac{7}{1}}{\dfrac{5}{8}}=\dfrac{7}{1}\times \dfrac{8}{5}$

$\dfrac{\dfrac{7}{1}}{\dfrac{5}{8}}=\dfrac{7\times 8}{1\times 5}$

$\dfrac{\dfrac{7}{1}}{\dfrac{5}{8}}=\dfrac{56}{5}$

Therefore, the correct option is D.

5 0

3 years ago

Read 2 more answers

Given sin B = .88 find angle B in radians. Round your answer to the nearest hundredth.

ELEN [110]

Use the inverse sine function on a calculator.

arcsin (0.88) = 1.08 radians

6 0

3 years ago

The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,

professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so $\mu = 7*0.6 = 4.2$

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150$

$P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630$

$P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323$

So

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103$

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

3 0

3 years ago