The inverse of the function f(x)= x^2 is a function.
<h3>The graph of the inverse</h3>
The equation of the function is
f(x)= x^2
Rewrite as:
y = x^2
Swap x and y
x = y^2
Make y the subject
![y = \sqrt x](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20x)
Rewrite as:
![f^{-1}(x) = \sqrt x](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%20%3D%20%5Csqrt%20x)
So, the inverse of f(x)= x^2 is ![f^{-1}(x) = \sqrt x](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%20%3D%20%5Csqrt%20x)
See attachment for the graph
<h3>Is the inverse a function?</h3>
The inverse is a function.
This is so because it passes the vertical line test
Read more about inverse functions at:
brainly.com/question/2883051
#SPJ1
A good estimate would be -10.
In order to estimate, start off by rounding both numbers to the nearest whole number. -7.94 can be rounded to -8 because the first number to the right of 7 is greater than 5. 2.31 can be rounded to 2 because the first number to the right of the 2 is less than 5.
After rounding, the expression becomes -8-2, which is equal to -10.
X^2 - 80 = 0
x^2 = 80 ...take the square root of both sides, eliminating the ^2
x = (+-) sqrt 80
x = (+-) sqrt 16 * 5
x = (+-) 4 sqrt 5
so x = 4 sqrt 5 or x = -4 sqrt 5