The formula for the sum of n terms in an arithmetic progression is:
S = n/2 * (2a + (n-1)d)
Here, the common difference, d, is 8 and the first term, a, is 1. Substituting these into the formula, we get:

S = n/2 * (2*1 + 8(n - 1))
S = n + 4n² - 4n
S = 4n² - 3n
The answer is A.

8 0

3 years ago

Let u = <-3, -5>, v = <-3, 1>. Find u + v. <-2, -8> <-8, -2> <0, -6> <-6, -4>

salantis [7]

Answer:

<-6,-4>

Step-by-step explanation:

To find u+v, all you have to do is add the corresponding components of each.

That is for example on this problem, you would do

<-3,-5>+<-3,1>

=<-3+-3,-5+1>

=<-6,-4>.

7 0

3 years ago