Answer:
768 bugs
Step-by-step explanation:
You can rewrite this problem as a function as time where the bug population is f(x), and x is the number of days since the start.
f(x)=6*2^(x/5)
Here, the 6 represents the number of bugs that you start with, the two shows that they double every day, and the /5 shows that they double every 5 days.
By plugging in 35, you get 6*2^7, which is 768.
Answer:
In this question if g and h is constant then;
111 = 14g
14g = 111
g = 111/14
g = 27.7 ~ 28
And also,
13.65 = h + 4.88
h + 4.88 = 13.65
h = 13.65 - 4.88
h = 8.77
Hope it helps!
The answer is P= 80/19
hope this helps
Answer:
Step-by-step explanation:
3b⁵ + 15b⁴ - 18b⁷ = 3b⁵ + [3*5*b⁴] - [6*3*b⁷]
=3b⁴*( b + 5 - 6b³)
We know that GCF stands for Greatest Common Factor and hence we need to apply this in solving the given problem. The solution is shown below:
54x+8154x+81
Combine same terms, we have:
8208X+81
Factoring with the greatest common factor which is 27
304x+3
The answer for the factored expression is 304X + 3.
