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Irina-Kira [14]
3 years ago
10

21 points!!

Mathematics
1 answer:
Bogdan [553]3 years ago
3 0

Answer:

See attached pictures.

Step-by-step explanation:

The sine and cosine functions have the forms: f(x) = C+ A sinBx and f(x) = C + A cosBx. A is the amplitude for each function. The period is found by dividing 2π the absolute value of B or \frac{2\pi}{|B|}. C shifts the function up and down.

The sine function always starts and ends on the x-axis.

The cosine function always starts and ends at the y=A.

6.) The sine function starts at (0,0) then peaks at 5. Comes down to 0 and down to -5 before returning to 0.

The amplitude is 5.

The period is \frac{2\pi}{|2|}=\pi

7.) Here A=3 so the amplitude is 3, B is 1/2 so the period is 4π. Start at (3,0) and descend down to (2π, 0). Go back up to (4π, 3).

8.) Here A = 2 so the amplitude is A. B is 2π so the period is 1. C is 1 so the graph is shifted up a unit.

Start the graph at (0,1) and go up to (0.25,3) and down to (0.5,1) and continue downward to (0.75, -3) then back up to (1,1).

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Jamal ran 7 kilometers, sprinted 400 meters, and climbed bleachers for a distance of 1.6 kilometers during track practice. How m
seraphim [82]
First, convert 7 kilometers to meters, which is 7000 meters.
Add that to 400, and now you he ran 7400 meters.
Now convert 1.6 kilometers to meters, which is 1600 meters.
Add that to 7400, and the total is 9000 meters.

Hope this helped!
4 0
3 years ago
Read 2 more answers
Can I please get some help with this :D
Luba_88 [7]
1. Anwser=53.3 (do 40*3 then anwser x 4)
2anwser=120
6 0
2 years ago
Use the divergence theorem to find the outward flux of the vector field F(x,y,z)=2x2i+5y2j+3z2k across the boundary of the recta
aksik [14]

Answer:

The answer is "120".

Step-by-step explanation:

Given values:

F(x,y,z)=2x^2i+5y^2j+3z^2k \\

differentiate the above value:

div F =2 \frac{x^2i}{\partial x}+5 \frac{y^2j}{\partial y}+3 \frac{z^2k }{\partial z}  \\

        = 4x+10y+6z

\ flu \ of \ x = \int  \int div F dx

              = \int\limits^1_0 \int\limits^3_0 \int\limits^1_0 {(4x+10y+6z)} \, dx \, dy \, dz \\\\ = \int\limits^1_0 \int\limits^3_0 {(4xz+10yz+6z^2)}^{1}_{0} \, dx \, dy  \\\\ = \int\limits^1_0 \int\limits^3_0 {(4x+10y+6)} \, dx \, dy  \\\\ = \int\limits^1_0  {(4xy+10y^2+6y)}^3_{0} \, dx   \\\\ = \int\limits^1_0  {(12x+90+18)}\, dx   \\\\= {(12x^2+90x+18x)}^{1}_{0}   \\\\= {(12+90+18)}   \\\\=30+90\\\\= 120

6 0
3 years ago
Divide.
melomori [17]
C. hope this helps:)
4 0
3 years ago
Read 2 more answers
Which numbers are equivalent to 3/10
Sedbober [7]

Answer:

Multiply numerator and denominator with same number to gwt the answers . There are infinitely many numbers

3/10 × 2/2 = 6/20

3/10 × 5/5 = 15/50

3/10 × 10/10 = 30/100

And so on

8 0
3 years ago
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