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Irina-Kira [14]
3 years ago
10

21 points!!

Mathematics
1 answer:
Bogdan [553]3 years ago
3 0

Answer:

See attached pictures.

Step-by-step explanation:

The sine and cosine functions have the forms: f(x) = C+ A sinBx and f(x) = C + A cosBx. A is the amplitude for each function. The period is found by dividing 2π the absolute value of B or \frac{2\pi}{|B|}. C shifts the function up and down.

The sine function always starts and ends on the x-axis.

The cosine function always starts and ends at the y=A.

6.) The sine function starts at (0,0) then peaks at 5. Comes down to 0 and down to -5 before returning to 0.

The amplitude is 5.

The period is \frac{2\pi}{|2|}=\pi

7.) Here A=3 so the amplitude is 3, B is 1/2 so the period is 4π. Start at (3,0) and descend down to (2π, 0). Go back up to (4π, 3).

8.) Here A = 2 so the amplitude is A. B is 2π so the period is 1. C is 1 so the graph is shifted up a unit.

Start the graph at (0,1) and go up to (0.25,3) and down to (0.5,1) and continue downward to (0.75, -3) then back up to (1,1).

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Answer:

C, D and E

Step-by-step explanation:

Assuming  

f(x) = √(9−8x)

and the options are:

A. p(x) = √(-8x) and q(x)=9+x

B. p(x) = √(9+x) and q(x)=8x

C. p(x) = √(-x) and q(x)=8x−9

D. p(x)=√(9−x) and q(x)=8x

E. p(x)=√x and q(x)=9−8x

F. p(x)=9−8x and q(x)=√x

G. All of the above

H. None of the above

Substituting in f(x)=p(q(x)) we get:

A. √(-8(9+x)) = √(-72 - 8x)

B. √(9+(8x)) = √(9+8x)

C. √(-(8x−9 )) = √(-8x + 9)

D. √(9−(8x)) = √(9−8x)

E. √(9−8x )

F. 9−8(√x ) = 9 - 8√x

8 0
3 years ago
Plz help worth 50 points
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Answer:

The answer is A

Step-by-step explanation:

Starting from -3 in the Y values of option A. If you subtract three from each value, you will get the next value to the right.

  • -3 minus -3 = -6
  • -6 minus -6 = -9

       

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Step-by-step explanation:

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