I don’t understand either
3x+3=9
x=2
that way the answer is 9
Answer:
Y=3
Step-by-step explanation:
-1= 1/2
1/2=-1
x=-1
y=3
Hope this helps!
Answer:
The answer is
<h2>

</h2>
Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
To find the equation of the parallel line we must first find the slope of the original line
From the question the original line is
y=1/4x+5
Comparing with the general equation above
Slope = 1/4
Since the lines are parallel their slope are also the same
Slope of parallel line = 1/4
So the equation of the line using point
(2,-9) and slope 1/4 is
<h3>

</h3>
We have the final answer as
<h3>

</h3>
Hope this helps you
Answer:
The correct answer is 24
Step-by-step explanation:
to solve this you will need to use the pathagreom theorum
a^{2}+b^{2}=c^{2}
A= one side lenth
B= the secons side lenth
C= hypotnuse
It is helpfull to draw out the situation
you know that the latter is 25 ft, that is your hypotnuse
you also know that the 7 ft away from the base of the building is one of the side lenths, lets call it side a
so plug the numbers into the equation
7^2 + b^2 = 25 ^2
you leave b^2 alone because that is the side you are trying to find
now square 7 and 25 but leave b^2 alone
49 + b^2 = 625
now subtract 49 from both sides
b^2 = 576
now to get rid of the square of b you have to do the opposite and square root both sides removing the square of the B and giving you the answer of..........
B= 24
Hope this helped!! I tryed to explain it as simpil as possiable