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Lerok [7]
2 years ago
12

Point JJJ is located at (-4, 4)(−4,4)left parenthesis, minus, 4, comma, 4, right parenthesis. Select all of the following that a

re 444 units from point JJJ. PLEASE I NEED IT TODAY RIGHT NOW IM BEGGING
Mathematics
1 answer:
In-s [12.5K]2 years ago
8 0

Answer:

(-4, 8), (-4, 0), (0, 4) and (-4, 0)

Step-by-step explanation:

Given that point J is located at (-4, 4). The point4 units from point J can either be up, down, left or right. Hence:

The point 4 units up of point J = (-4, 4 + 4) = (-4, 8)

The point 4 units down of point J = (-4, 4 - 4) = (-4, 0)

The point 4 units right of point J = (-4 + 4, 4) = (0, 4)  

The point 4 units left of point J = (-4, 4 - 4) = (-4, 0)

Therefore the points that are 4 units from point  J are (-4, 8), (-4, 0), (0, 4) and (-4, 0).

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People were surveyed about the types of pets they own and their housing situation. Each person has only one pet. For people who
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The answer is 6.3

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2 years ago
A 555-mile, 5-hour plane trip was flown at two speeds. For the first part of the trip, the average speed was 105 mph. Then the t
Pepsi [2]

Answer:

Hence Distance traveled at speed 115 mph is <u>345 miles</u> and Distance traveled at speed 105 mph is <u>210 miles</u>.

Step-by-step explanation:

Given:

Total Distance = 555 mile

Total time = 5 hour

Let time taken to travel at 115 mph be t

So Time taken to travel at 105 mph will be equal to difference between Total time and  time taken to travel at 115 mph.

Time taken to travel at 105 mph = 5-t

Distance traveled in speed 105 mph will be equal to speed multiplied by time taken to travel at 105 mph.

Framing in equation form we get;

Distance traveled in 115 mph = 115t

Also;

Distance traveled in speed 105 mph will be equal to speed multiplied by time taken to travel at 105 mph.

Framing in equation form we get;

Distance traveled in 105 mph = 105(t-5) = 105t - 525

Now Total Distance traveled is equal sum of Distance traveled in 115 mph and Distance traveled in speed 105 mph

115t-(105t-525)=555\\\\115t-105t+525=555\\\\10t+525=555\\\\10t=555-525\\\\10t=30\\\\t=\frac{30}{10}=3

Time taken to travel at 115 mph = 3 hrs.

Time taken to travel at 105 mph = 5-t=5-3=2\ hrs

Now Distance traveled in 115 mph = 115t = 115 \times 3 = 345\ miles

Distance traveled in 105 mph = 105(5-t) = 105(5-3)= 105\times 2 = 210\ miles

Hence Distance traveled at speed 115 mph is <u>345 miles</u> and Distance traveled at speed 105 mph is <u>210 miles</u>.

6 0
2 years ago
Please help (picture above)
Slav-nsk [51]

Answer:

y= 45

x=9

Step-by-step explanation:

plug 5x into y since y=5x:

5x=4x+9

-4. -4

x=9

5(9)=45

5 0
2 years ago
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e=7

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This * ' * is 2 square

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3 years ago
How to write 111101 to base 2
Hoochie [10]

Answer:

11011000111111101

Step-by-step explanation:

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