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Lerok [7]
2 years ago
12

Point JJJ is located at (-4, 4)(−4,4)left parenthesis, minus, 4, comma, 4, right parenthesis. Select all of the following that a

re 444 units from point JJJ. PLEASE I NEED IT TODAY RIGHT NOW IM BEGGING
Mathematics
1 answer:
In-s [12.5K]2 years ago
8 0

Answer:

(-4, 8), (-4, 0), (0, 4) and (-4, 0)

Step-by-step explanation:

Given that point J is located at (-4, 4). The point4 units from point J can either be up, down, left or right. Hence:

The point 4 units up of point J = (-4, 4 + 4) = (-4, 8)

The point 4 units down of point J = (-4, 4 - 4) = (-4, 0)

The point 4 units right of point J = (-4 + 4, 4) = (0, 4)  

The point 4 units left of point J = (-4, 4 - 4) = (-4, 0)

Therefore the points that are 4 units from point  J are (-4, 8), (-4, 0), (0, 4) and (-4, 0).

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Penyelesaian : 
Akar-akar persamaan lama :  x1 dan x2
                                             
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                                             xA = 2x1 - 1
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                                             xA + xB  = (2x1 - 1) + (2x2 - 1)
                                                           = 2 (x1 + x2) - 2
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                                              xA . xB = -4
    
Jadi persamaan kuadrat baru : x² - (xA + xB)x + xA . xB = 0
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