Are you trying to simply the equation if so x = 6
Answer:
13.2 miles
Step-by-step explanation:
To solve this, we will need to first solve for the base of the triangle and then use the information we find to solve for the shortest route.
(5.5 + 3.5)² + b² = 15²
9² + b² = 15²
81 + b² = 225
b² = 144
b = 12
Now that we know that the base is 12 miles, we can use that and the 5.5 miles in between Adamsburg and Chenoa to find the shortest route (hypotenuse).
5.5² + 12² = c²
30.25 + 144 = c²
174.25 = c²
13.2 ≈ c
Therefore, the shortest route from Chenoa to Robertsville is about 13.2 miles.
Answer:
A. -61/9
Step-by-step explanation:
(7x + 28) + (7x +28) = 5x - 5 . . . . . . . given equation
14x +56 = 5x -5 . . . . . . . . . . . . . . . . . collect terms
9x = -61 . . . . . . . . . . . . . . . . . . . . . . . . subtract 5x+56
x = -61/9 . . . . . . . . . . . . . . . . . . . . . . . . divide by the coefficient of x
Answer:44 ft
Step-by-step explanation:
P=2(l+w)
P=2(14+8)
P=2(22)
P=44
For q5: x=-5/4, y=-15/8
q6: x=-23/5, y=4/5
q7: x=-4/5 y=0
q8: x=6, y=4
