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3 years ago

Which inequality is equivalent to 7x-2y> 8.

1 answer:

6 0

$7x-2y> 8 \ \ -7x \\ \\7x -7x-2y> 8 -7x \\ \\ -2y >8-7x \ \ / : (-2)\\ \\\frac{-2}{-2}\cdot y < \frac{8}{(-2)}-\frac{7}{(-2)}x \\ \\ y < \frac{7}{ 2}x -4 \\ \\ \\ Answer : \ c) \ y < \frac{7}{2}x-4$

$If \ we \ multiply \ or \ divide \ both \ sides \ of \ an \ inequality \ by \ a \ negative \\ \\number \ we \ have \ to \ switch \ the \ direction \ of \ the \ inequality$

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Brianna wants to buy a digital camera for a photography class. One store offers the camera for $48 down and a payment plan of $2

tatyana61 [14]

Answer:

the second store

Step-by-step explain: the second store is 244 but the first store is 300..i hope this helps. 14*12+76=244 and 21*12 + 48 is 300

7 0

3 years ago

The waking time of a student under common conditions is normally distributed with mean of 30 hours and a standard deviation of 5

Elina [12.6K]

Answer:

If the walking time is greater than or equal to 38.225 hours, than it exceeds 95% probability that is lie in top 5%.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 30 hours

Standard Deviation, σ = 5 hours

We are given that the distribution of waking time is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.95

$P( X < x) = P( z < \displaystyle\frac{x - 30}{5})=0.95$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 30}{5} = 1.645\\\\x = 38.225$

Thus, if the walking time is greater than or equal to 38.225 hours, than it exceeds 95% probability that is lie in top 5%.

4 0

3 years ago

Help solve algebra 15a=6a-90

AleksandrR [38]

15a =6a - 90

Move all the numbers with variables to one side

15a - (6a) = 6a -(6a) -90
9a = -90
9a/9 = -90/9
a = -9

Hope this helps

5 0

2 years ago

The Frostburg-Truth bus travels on a straight road from Frostburg Mall to Sojourner Truth Park. The mall is 3 miles west and 2 m

Verizon [17]

To start, write your locations as points, with north and south being positive and negative y respectively and east and west being positive and negative x respectively. Doing this gives us the mall at (-3,-2) and the park at (4,5). Now, we use our distance formula $( \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 } )$ to solve for the unknown distance. Plugging in with the park values as our second values and our mall values as our first values (as well as with our unknown distance as d), we get $d= \sqrt{(4-(-3))^2+(5-(-2))^2} = \sqrt{(7)^2+(7)^2} = \sqrt{49+49} = \sqrt{98}$ . This square root can be rounded to 9.9 miles.

4 0

3 years ago

A. 37<br> B. 38<br> C. 39<br> D. 40

Dvinal [7]

Hello ^w^

I believe the answer you are looking for is A

I found this answer by adding up the lengths of all the sides.

S -> T = 8

S -> R = 7

Q -> R = 6

P -> Q = 6

P -> T = 10

10 + 6 + 6 + 7 + 8 -> 37

A -> 37

If I am incorrect, please inform me.

Have a good day!

4 0

2 years ago