No, this would not be a linear function. Being linear means it creates a straight line, but this function has an x squared. Anytime x^2 is in a function, the graph is a u shape, called a parabola. A simple linear function is y=x :D
Answer:
f(x) = -(x-3)^2 + 4
Step-by-step explanation:
(h; k) are the coordinates of the vertex.
On the graph are (3, 4), therefore we have:
f(x) = a(x-3)^2 + 4
We have the x- intercept (1,0) -> x=1; y=0.
Substitute them into the equation:
0 = a(1 - 3)^2 + 4
0 = a(-2)^2 + 4
4a + 4 = 0 | -4
4a = -4 |-4
a = -1
So, we have the answer:
f(x) = -(x-3)^2 + 4
Y = x^2 + 8x - 3
y = x^2 + 8x + (8/2)^2 - 3 - (8/2)^2
y = x^2 + 8x + 16 - 3 - 16
The two fractions that added together give you a sum of -7/24 are 1/24+-8/24= -7/24
Answer:
5/12
Step-by-step explanation:
You want the tangent of angle F in right triangle FGH with sides FG=24, GH=10, and FH=26.
<h3>Tangent</h3>
The mnemonic SOH CAH TOA is intended to remind you of the relations between trig functions and the sides of a right triangle. The TOA part of this tells you ...
Tangent = Opposite/Adjacent
<h3>Application</h3>
The side opposite angle F is GH = 10.
The side adjacent to angle F is FG = 24.
Then the tangent is ...
tan(F) = GH/FG = 10/24
tan(F) = 5/12 . . . . . reduced to lowest terms
