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emmasim [6.3K]
3 years ago
13

A solution to the equation 2x^2+3x+2=0 is

Mathematics
1 answer:
Sidana [21]3 years ago
7 0
0 is a solution to this equation.
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(4x^3-3x^2+5x+6) /(x+6) what is the quotient
lawyer [7]

Answer:

(4x2 + x + 6) • (x - 1)

———————————————————————

x + 6

3 0
3 years ago
What is the domain in the equation y=x+1?
jeka57 [31]

Answer:

  all real numbers

Step-by-step explanation:

The domain of <em>any polynomial function</em> is "all real numbers." There is no value of x for which y is undefined.

7 0
4 years ago
-2.2 + (-3.7 +(-1.4) =(-2-2 + (-3. 7) + (-1.4)<br>+ (-2:24<br>S1-3​
Luda [366]
6 because it has donuts
5 0
4 years ago
What is the equation for the points (-9,7) and (-6,-3)
andriy [413]

In point slope form, the equation is y-7=(-10/3)(x+9).  In slope-intercept form, it is y=(-10/3)x-23.

First find the slope of the line.  The formula for slope is

m=(y₂-y₁)/(x₂-x₁)

Using our points, we have  

m=(-3-7)/(-6--9) = -10/3

Plug this into point slope form:

y-y₁=m(x-x₁)

y-7=(-10/3)(x--9)

y-7=(-10/3)(x+9)

Using the distributive property:

y-7=(-10/3)*x+(-10/3)*9

y-7=(-10/3)x-90/3

y-7=(-10/3)x-30

Add 7 to both sides:

y=(-10/3)x-23

4 0
3 years ago
If you invest $ 30 , 700 with an annual interest rate of 8.9 % , compounded daily, how much would you have at the end of 4 years
alexandr402 [8]

Answer: $43,823.37

Step-by-step explanation:

Formula to calculate the accumulated amount earned on principal (P) at rate of interest (r) compounded daily after t years :

A=P(1+\dfrac{r}{365})^{365t}

As per given , we have

P= $ 30,700

r= 8.9 % = 0.089

t= 4 years

A=30700(1+\dfrac{0.089}{365})^{365(4)}\\\\=30700(1+0.0002438)^{365(4)}\\\\=30700(1.0002438)^{1460}\\\\=30700(1.42747138525)\\\\=43823.3715272\approx43823.37

Hence, the amount at the end of 4 years would be $43,823.37 .

6 0
3 years ago
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