Answer:
Step-by-step explanation:
Hi!
Here is the formula for point slope form: y-y1=m(x-x1)
Our slope in this case is 5, and our points are (1, 9). 1(x1) and 9(y1)
So, if we substitute our given data into the formula, here is what we will get.
y-9=5(x-1)
Thus, our answer should be:
y-9=5(x-1)
I hope this helps!
:)
Answer:
49
Step-by-step explanation:
substitute b = - 6 and c = 7 into the expression and evaluate
c - 7b = 7 - (7 × - 6) = 7 - (- 42) = 7 + 42 = 49
Questions 1, 2, 3, and 4 are exercises to give you practice with
common denominators. For each of these questions, change all
the fractions to common denominators, and the answers jump out at you.
#1). 5/12 = 25/60
2/5 = 24/60
Make um negative, and then you'll have the answer right away.
#2). The one that's negative is obviously the least.
Both positive ones must be bigger than the negative one.
For the positive ones:
2/5 = 6/15
2/3 = 10/15 .
Now it's easy.
#3). This is tough. The least common denominator is 2,520 !
It's probably easier to just do the divisions and get the decimals
for each fraction.
-5/8 = -0.625
-7/9 = -0.777...
-4/5 = -0.8
-3/7 = -0.428...
Now it's easy to line um up.
#4). Sneaky one.
Look closely at each fraction.
B, C, and D are all less than 1, so they're not between 1 and anything more than 1.
8/5 is the only one that's more than 1.
#5). A fraction is just a short way to write a division problem.
When you see a fraction, it means
"the top number divided by the bottom number" .
When you actually do the division, the quotient you get
is the decimal form of the fraction.
To change a decimal into a percent,
move the decimal point two places that way ==> .
The numbers in the boxes at the bottom of #5 are the correct numbers,
but they both should be negative. (because the -3/8 is negative)
I believe the correct answer is true. According to the square root property, the solution set of x^2 = 25 is {±5}. <span>The </span>square root property<span> is one method that is used to find the solutions to a quadratic (second degree) equation. This method involves taking the </span>square roots <span>of both sides of the equation. Hope this answers the question.</span>
