Which ratio best defines experimental probability?

BRAINLIEST!!!

goldenfox [79]

Answer: $\frac{8}{17}$ or 8:17

Step-by-step explanation:

For any angle x (other than right angle) in a right triangle ,the trigonometric ratio of sin x is given by :-

$\sin x=\frac{\text{side opposite to x}}{\text{Hypotenuse}}$

Given: A right triangle with hypotenuse = 68 units

The side adjacent to S = 60

Let h be the side opposite to S, then using Pythagoras in the given right triangle, we get

$(68)^2=60^2+h^2\\\\\Rightarrow\ h^2=68^2-60^2\\\\\Rightarrow\ h^2=1024\\\\\Rightarrow\ h=\sqrt{1024}=32$

Thus, the side opposite to S = 32 units

Now, the trigonometric ratio for sin S is given by :-

$\sin S=\frac{\text{side opposite to S}}{\text{Hypotenuse}}\\\\\Rightarrow\sin S=\frac{32}{68}=\frac{8}{17}$

Hence, the trigonometric ratio for sin S = $\frac{8}{17}$ or 8:17

5 0

3 years ago

A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random

Yuliya22 [10]

Answer:

b) independent samples t-test

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

Step-by-step explanation:

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2\neq 0$

Our notation on this case :

$n_1 =5$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

We can calculate the mean and deviation for eaach group with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_1 =5.92$ represent the sample mean for the group 1

$\bar X_2 =5.74$ represent the sample mean for the group 2

$s_1=1.88$ represent the sample standard deviation for group 1

$s_2=1.81$ represent the sample standard deviation for group 2

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}$

And now we can calculate the statistic:

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

The degrees of freedom are given by:

$df=5+5-2=8$

And now we can calculate the p value using the altenative hypothesis:

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

7 0

3 years ago

WILL GIVE BRAINLIEST!!!

ELEN [110]

Answer:

C is the answer.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find the x-intercept of the parabola with vertex (1,-13) and y-intercept (0,-11).

Advocard [28]

1. find equation

general solutions are:
$y = a x^{2} +bx +c \\ \\ \frac{dy}{dx} = 2ax +b$

for P(0,-11)

$-11 = 0a + 0b +c$ ⇒ $c = -11$

for p(1,-13)
$-13 = 1a + 1b -11 \\ a+b = -2$

and

$0 = 2a + b \\ b = -2a$

solve for a and b:
$a - 2a = -2 \\ a = 2 \\ b = -4$

the total equation is now:

$y = 2 x^{2} -4x -11$

To find the x-intercept set y=0 and solve for x

$0 = 2 x^{2} -4x-11$

4 0

3 years ago

Read 2 more answers

Angie and Kenny play online video games. Angie buys 1 software package and 1 month of game play. Kenny buys 1 software package a

balandron [24]

The cost of one month of game play is $14

Step-by-step explanation:

Angie and Kenny play online video games

Angie buys 1 software package and 1 month of game play
Kenny buys 1 software package and 3 months of game play
Each software package costs $20
If their total cost is $96

We need to find the cost of one month of game play

∵ Angie buys 1 software package

∵ Kenny buys 1 software package

∵ Each software package costs $20

- Find the total cost of their software package

∴ The total cost of their software package = 20 × 1 + 20 × 1

∴ The total cost of their software package = 20 + 20 = 40

∴ The total cost of their software package is $40

Assume that the cost of one month of game play is $x

∵ The cost of one month of game play = x

∵ Angie buys 1 month of game play

∵ Kenny buys 3 months of game play

- Find the total cost of their game play

∴ The total cost of their game play = x × 1 + x × 3

∴ The total cost of their game play = x + 3x = 4x

∴ The total cost of their game play is $4x

∵ Their total cost is $96

- Add the costs of their software package and their game

play and equate the sum by 96

∴ 40 + 4x = 96

- Subtract 40 from both sides

∴ 4x = 56

- Divide both sides by 4

∴ x = 14

The cost of one month of game play is $14

Learn more:

You can learn more about the word problems in brainly.com/question/10557938

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4 0

3 years ago