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3 years ago

TerminatingRepeatingDecimalsCardSortActivity

Mathematics

1 answer:

yulyashka [42]3 years ago

8 0

Is there supposed to be a picture or is this just random

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Point G is the midpoint of PQ. <br> PG equals 2X plus 3 and GQ equals 5X -5. what is X?

borishaifa [10]

Answer:

$x=\frac{8}{3}=2\frac{2}{3}\approx{2.667}$

Step-by-step explanation:

$\overline{PG}=2x+3\\\overline{GQ}=5x-5$

Since they're equidistant (equal distances), we can set them equal to one another and solve for x:

$2x+3=5x-5$

Adding 5 to both sides:

$2x+8=5x$

Subtracting 2x from both sides:

$8=3x$

Dividing both sides by 3:

$\frac{8}{3}=x$

Therefore:

$x=\frac{8}{3}=2\frac{2}{3}\approx{2.667}$

6 0

3 years ago

Which expression has the largest coefficient. Will mark brainliest. Plz include explanation.

slamgirl [31]

Answer:

Expression 3

Step-by-step explanation:

State that a coefficient is a multiplicative factor, is a number in front of a variable, in some term of a polynomial.

The coefficients of the expression 3, for example, are 3, 7 and 24.

4 0

3 years ago

Please help me I need to solve for x.

Sav [38]

Answer: x=7

12x-4=0.5(22x+6)
12x-4=11x+3
-11x -11x
x=7

Explanation: use the tangent-chord angle theorem.

4 0

3 years ago

Please someone what is the total surface area of this pryamid

Dimas [21]

Answer:

$\large\boxed{C.\ (25+25\sqrt3)\ in^2}$

Step-by-step explanation:

We have the square and four equilateral triangles.

The formula of an area of a squre:

$A_S=a^2$

a - length of side

The formula of an area of an equilateral triangle:

$A_T=\dfrac{a^2\sqrt3}{4}$

a - length of side

Clculate the areas:

SQURE:

$A_S=x^2\ in^2$

TRIANGLE:

$A_T=\dfrac{x^2\sqrt3}{4}\ in^2$

The SURFACE AREA of a square pyramid:

$S.A.=A_S+4A_T\\\\S.A.=x^2+4\cdot\dfrac{x^2\sqrt3}{4}=x^2+x^2\sqrt3$

Put x = 5:

$S.A.=5^2+5^2\sqrt3=(25+25\sqrt3)\ in^2$

7 0

3 years ago

Write an inequality from (–5) to (–1) inclusive

skad [1K]

Answer:

$-5\leq x\leq -1$

Step-by-step explanation:

This is a compound inequality that basically states that the X value is greater than or equal to -5, but less than or equal to -1. It is inclusive, because it includes both numbers and therefore should have an equal to sign ( $\leq or \geq$ ) instead of just less than or greater than ( < or >).

8 0

3 years ago