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Arturiano [62]
3 years ago
8

TerminatingRepeatingDecimalsCardSortActivity

Mathematics
1 answer:
yulyashka [42]3 years ago
8 0
Is there supposed to be a picture or is this just random
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Point G is the midpoint of PQ. <br> PG equals 2X plus 3 and GQ equals 5X -5. what is X?
borishaifa [10]

Answer:

x=\frac{8}{3}=2\frac{2}{3}\approx{2.667}

Step-by-step explanation:

\overline{PG}=2x+3\\\overline{GQ}=5x-5

Since they're equidistant (equal distances), we can set them equal to one another and solve for x:

2x+3=5x-5

Adding 5 to both sides:

2x+8=5x

Subtracting 2x from both sides:

8=3x

Dividing both sides by 3:

\frac{8}{3}=x

Therefore:

x=\frac{8}{3}=2\frac{2}{3}\approx{2.667}

6 0
3 years ago
Which expression has the largest coefficient. Will mark brainliest. Plz include explanation.
slamgirl [31]

Answer:

Expression 3

Step-by-step explanation:

State that a coefficient is a multiplicative factor, is a number in front of a variable, in some term of a polynomial.

The coefficients of the expression 3, for example, are 3, 7 and 24.

4 0
3 years ago
Please help me I need to solve for x.
Sav [38]
Answer: x=7

12x-4=0.5(22x+6)
12x-4=11x+3
-11x -11x
x=7

Explanation: use the tangent-chord angle theorem.
4 0
3 years ago
Please someone what is the total surface area of this pryamid ​
Dimas [21]

Answer:

\large\boxed{C.\ (25+25\sqrt3)\ in^2}

Step-by-step explanation:

We have the square and four equilateral triangles.

The formula of an area of a squre:

A_S=a^2

a - length of side

The formula of an area of an equilateral triangle:

A_T=\dfrac{a^2\sqrt3}{4}

a - length of side

Clculate the areas:

SQURE:

A_S=x^2\ in^2

TRIANGLE:

A_T=\dfrac{x^2\sqrt3}{4}\ in^2

The SURFACE AREA of a square pyramid:

S.A.=A_S+4A_T\\\\S.A.=x^2+4\cdot\dfrac{x^2\sqrt3}{4}=x^2+x^2\sqrt3

Put x = 5:

S.A.=5^2+5^2\sqrt3=(25+25\sqrt3)\ in^2

7 0
3 years ago
Write an inequality from (–5) to (–1) inclusive
skad [1K]

Answer:

-5\leq x\leq -1

Step-by-step explanation:

This is a compound inequality that basically states that the X value is greater than or equal to -5, but less than or equal to -1. It is inclusive, because it includes both numbers and therefore should have an equal to sign (\leq   or \geq) instead of just less than or greater than ( < or >).

8 0
3 years ago
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