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3 years ago

May I have help on these two please, it’s for my sister?

Mathematics

1 answer:

Vanyuwa [196]3 years ago

4 0

#4.) 4
#5.) 3

Answers gotta be 20 characters long so ignore this part lol

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Pls answer quickly and lots of details

Elina [12.6K]

Answer:

=> 2.7 × 10³ × 8 × 10² / 4 × 10^-6

=> 2.7 × 8 × 10^3+2+6 /4

=> 5.4 × 10¹¹

5.4 × 10^11

8 0

3 years ago

One positive number exceeds three times another positive number by 5. The product of the two numbers is 68. Find the number

kati45 [8]

Answer:12

Step-by-step explanation:

Let the numbers be a and b

a-3b=5 ........equation (1)

There product is :

ab=68 ..........equation (2)

From equation (1)

a-3b=5

Make a the subject of the formula

a=5+3b. ........equation (3)

Substitute equation (3) into equation (2)

(5+3b)b=68

3(b^2)+3b-68=0

The product is -204b^2(17 and -12)

(b+17)(b-12)=0

b=-17 or b=12

So the number is 12

6 0

3 years ago

Beth is putting liquid fertilizer on the plants in 4 flowerpots. her measuring spoon holds 1/8 teaspoon the directions say to pu

VARVARA [1.3K]

20 times 1/8+1/8+1/8+1/8+1/8=5/8 times 4 because of the four pots = 20

5 0

3 years ago

Read 2 more answers

X-4y-8=6/8+-8y-2y<br>5y-3(6-7/8)=5x-4y+3

Ivan

First simplify

x-4y-8=3/4-10y
add 10y both sides and add 8
x+6y=8+3/4
times 4 both sides
4x+24y=32+3
4x+24y=35

5y-3(6-7/8)=5x-4y+3
add 4y both sides
9y-3(6-7/8)=5x+3
distribute
9y-18+21/8=5x+3
minus 5x both sides
9y-5x-18+21/8=3
add 18 to both sides and minus 21/8 both sides
9y-5x=21-21/8
times 8 both sides
72y-40x=147
72y-40x=147

so we got

24y+4x=35
72y-40x=147

multiply first equation by -3 and add to 2nd

-72y-12x=-105
72y<span>-40x=147 +</span>
0y-52x=42

-52x=42
divide both sides by -52
x=-21/26
sub back

24y+4x=35
24y+4(-21/26)=35
using math
y=497/312

the solution is
$( \frac{-21}{26}, \frac{497}{312} )$

8 0

3 years ago

Point P is the interior of LaTeX: \angle OZQ.\:∠ O Z Q .If LaTeX: m\:\angle\:OZQ\:m ∠ O Z Q= 125 and LaTeX: m\angle OZP\:m ∠ O Z

saw5 [17]

Answer:

Step-by-step explanation:

If point P is the interior of ∠OZQ , then the mathematical operation is true;

∠OZP + ∠PZQ = ∠OZQ

Given parameters

∠OZQ = 125°

∠OZP = 62°

Required

∠PZQ

TO get ∠PZQ, we will substitute the given parameters into the expression above as shown

∠OZP + ∠PZQ = ∠OZQ

62° + ∠PZQ = 125°

subtract 62° from both sides

62° + ∠PZQ - 62° = 125° - 62°

∠PZQ = 125° - 62°

∠PZQ = 63°

<em>Hence the value of ∠PZQ is 63°</em>

6 0

3 years ago