Yes it can and the answer would be 0.5
Terminating decimals are numbers that never stop going after the period. Such an example would be 10/3 which would give 3.333333 indefinitely. 1/2 gives a whole number, that is, 0.5
Answer:
see below
Step-by-step explanation:
Choose a couple of values for x. Figure out the corresponding values for y. Plot those points and draw a line through them.
Let's choose x=0 and x=4. Then the corresponding y-values are ...
y = 2·0 = 0 . . . . . point (x, y) = (0, 0)
y = 2·4 = 8 . . . . . point (x, y) = (4, 8)
These are graphed below.
We will have to use the formula for the area of a trapezoid on this problem, which is (
and
are the bases of the trapezoid and
is the height):

All we need to do is substitute the information we are given into our formula:

Now, let's just simplify the equation:




The missing base has a length of 13 units.
Answer:
Table 3
Step-by-step explanation:
The third one.
We have the function
![h(x) = \sqrt[3]{-x+2}](https://tex.z-dn.net/?f=h%28x%29%20%3D%20%5Csqrt%5B3%5D%7B-x%2B2%7D)
Now we will insert values of x in that definition o h(x) and see if the values we obtain match the corresponding y values in the table:
![h(-6) = \sqrt[3]{-(-6)+2}= \sqrt[3]{6+2}= \sqrt[3]{8} = 2\\h(1) = \sqrt[3]{-1+2}= \sqrt[3]{1}= 1\\h(2) = \sqrt[3]{-2+2}= \sqrt[3]{0}= 0\\h(3) = \sqrt[3]{-3+2}= \sqrt[3]{1}= 1\\h(10) = \sqrt[3]{-10+2}= \sqrt[3]{-8}= -2](https://tex.z-dn.net/?f=h%28-6%29%20%3D%20%5Csqrt%5B3%5D%7B-%28-6%29%2B2%7D%3D%20%5Csqrt%5B3%5D%7B6%2B2%7D%3D%20%5Csqrt%5B3%5D%7B8%7D%20%3D%202%5C%5Ch%281%29%20%3D%20%5Csqrt%5B3%5D%7B-1%2B2%7D%3D%20%5Csqrt%5B3%5D%7B1%7D%3D%201%5C%5Ch%282%29%20%3D%20%5Csqrt%5B3%5D%7B-2%2B2%7D%3D%20%5Csqrt%5B3%5D%7B0%7D%3D%200%5C%5Ch%283%29%20%3D%20%5Csqrt%5B3%5D%7B-3%2B2%7D%3D%20%5Csqrt%5B3%5D%7B1%7D%3D%201%5C%5Ch%2810%29%20%3D%20%5Csqrt%5B3%5D%7B-10%2B2%7D%3D%20%5Csqrt%5B3%5D%7B-8%7D%3D%20-2)
We can see that the values match the table 3, so the table 3 represents points on the graph of h(x)
1) 8
2) 14.5*2=29
3) 7x+5=2*13, 7x+5=26, 7x=21, x=3
4)d(1)=2r,
if r increase 3 times, d(2)=2*(3r)
d(2)/d(1)=(2*3r)/2r=3,
so diameter increases 3 times