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3 years ago

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A box contains 19 large marbles and 11 small marbles. Each marble is either green or white. 3 of the large marbles are green, an

d 4 of the small marbles are white. If a marble is randomly selected from the box, what is the probability that it is large or green

1 answer:

loris [4]3 years ago

8 0

Answer:

Step-by-step explanation:

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If one jar of coffee costs $y, what will be the cost of four jars of coffee

Gnoma [55]

4 jars of coffee is going to cost 4 times $4

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3 years ago

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I need help with 25 i dont know how to put it on a double line bar

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Use proportion
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4 years ago

If you are dealt five cards from a shuffled deck of 52 cards find the probability of getting three queens and two kings

dexar [7]

The probability of getting three queens and two kings is $\frac{1}{1082900}$

<u>Solution:</u>

Given that , you are dealt five cards from a shuffled deck of 52 cards

We have to find the probability of getting three queens and two kings

Now, we know that, in a deck of 52 cards, we will have 4 queens and 4 kings.

$\text { probability of an event }=\frac{\text { favarable possibilities }}{\text { number of possibilities }}$

<em><u>Probability of first queen:</u></em>

$\text { Probability for } 1^{\text {st }} \text { queen }=\frac{4}{52}=\frac{1}{13}$

<em><u>Probability of second queen:</u></em>

$\text { Plobability for } 2^{\text {nd }} \text { queen }=\frac{3}{51}=\frac{1}{17}$

Here we used 3 for favourable outcome, since we already drew 1 queen out of 4

And now number of outcomes = 52 – 1 = 51

<em><u>Probability of third queen:</u></em>

Similarly here favorable outcome = 2, since we already drew 2 queen out of 4

And now number of outcomes = 51 – 1 = 50

$\text { Probability of } 3^{\text {rd }} \text { queen }=\frac{2}{50}=\frac{1}{25}$

<em><u>Probability for first king:</u></em>

Here kings are 4, but overall cards are 49 as 3 queens are drawn

$\text { probability for } 1^{\text {st }} \text { king }=\frac{4}{49}$

<em><u>Probability for second king:</u></em>

Here, kings are 3 and overall cards are 48 as 3 queens and 1 king are drawn

$\text { probability of } 2^{\text {nd }} \text { king }=\frac{3}{48}=\frac{1}{16}$

<em><u>And, finally the overall probability to get 3 queens and 2 kings is:</u></em>

$=\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} \times \frac{4}{49} \times \frac{1}{16}=\frac{4}{4331600}=\frac{1}{1082900}$

Hence, the probability is $\frac{1}{1082900}$

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3 years ago

Storm spent less than 9 hours memorizing and filming a scene that was 6 pages long in script. Express this as an inequality usin

amid [387]

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Step-by-step explanation

i Got it by calculating the varible s with 9 over with 6

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3 years ago

The expression below shows the population of squirrels in a forest after 3x years: f(x) = 30(1.03)3x Which of the following is a

amm1812

<span>the population of squirrels in a forest after 3x years: f(x) = 30(1.03)3x
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</span>

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4 years ago