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Kay [80]
3 years ago
15

Determine the solution of the system. Show your work

Mathematics
1 answer:
Oxana [17]3 years ago
3 0
First question:

1. Set equations equal to each other so 5x-9=2x+6
2. Put x's on one side so that 3x=15
3. Divide by 3 so that x=15
4. Substitute 15 in for x so that y=2(15)+6
5. Solve for y so that y=36
6. Thus the equations intersect at (15,36)

Second question:

1. Since for lines y=mx+b, and m=slope=3 you only need to write an equation with slope 3
2. y=3x+b, b can be any number
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Rauol measured the height of 12 different plants in his garden in April. He measured them again in June. What is the difference
jasenka [17]

The question is incomplete. Here is the complete question.

Raoul measured the ehight of 12 different plants in his garden in April. He measured them again in June.

April Heights (in inches) 12 15 23 11 42 45 44 39 12 19 20 12

June Heights (in inches) 45 45 40 43 11 14 12 13 41 40 45 41

What is the difference between the mean height in April and the mean height in June?

Answer: The difference between means is 8.0

Step-by-step explanation: <u>Mean</u> is the average of a set of numbers.

It is calculated as:

\mu=\frac{\Sigma x}{n}

where

x is the numbers in the set

n is how many numbers are there in the set

For heights in April, the mean is:

\mu_{1}=\frac{12+15+23+11+42+45+44+39+12+19+20+12}{12}

μ₁ = 24.5

For heights in June, the mean os:

\mu_{2}=\frac{45+45+40+43+11+14+12+13+41+40+45+41}{12}

μ₂ = 32.5

The difference between means:

μ₂ - μ₁ = 32.5 - 24.5 = 8.0

The difference between the mean height in April and in June is 8.0 inches.

3 0
2 years ago
What is the area of
Inessa05 [86]
I hope this helps you




Area=2.6


Area=12
4 0
3 years ago
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F(x)=⅔x⁴-12x²+x+⅞ its apolynomial function or its not polynomial function
baherus [9]

Answer:

apolinomlia

Step-by-step explanation:

7 0
2 years ago
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Andre is setting up rectangle tables for a party. He can fit 6 chairs around a single table. Andre lined up 10 tables end to end
IRINA_888 [86]
If there is one table (t=1) then 6 chairs (c=6) can be placed around the table, 2 along the length on each side and 1 at each end.
When t=2, and the tables are end to end (joined at their width) c=10, that is, 4 chairs on each side of the double table and 1 at each end. Each time a table is added c increases by 4 so we can write c=4t+2 the constant 2 being the single chair at each end. If the tables are separated then c=6t.
5 0
3 years ago
The mass, m kilograms, of a horse is 429 kg, correct to the nearest kilogram.
Liula [17]

Answer:

400 < m< 430 kg

Step-by-step explanation:

the mass of horse is 429 kg

estimated to the nearest hundred is 400  kg

estimated to the nearest  tens is 430 kg

thus the value of m mass lies between 400 to 430

therefore

400 < m< 430 kg

6 0
1 year ago
Read 2 more answers
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