Question

The sides of a square are three to the power of two sevenths inches long. What is the area of the square?

Answer 1

The area is (3^{2/7} )^2[/tex], or 

Answer 2

we know that

Area of the square=$x^{2}$

where

x is the length side of the square

in this problem

$x=3^{\frac{2}{7}}$ in

so

$Area=(3^{\frac{2}{7}})^{2} \\ Area=3^{\frac{(2*2)}{7}} \\ Area=3^{\frac{4}{7}}$in²

therefore

the answer is the option

three to the power of four sevenths square inches