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Law Incorporation [45]
3 years ago
9

Please help i’m so confused asap!!!!!

Mathematics
1 answer:
Ivanshal [37]3 years ago
4 0

Answer:

I would say the second car.

Step-by-step explanation:

372/15.2 = 24 miles per gallon

198/7.2 = 27.5 miles per gallon

So the answer is the second car is better on gas mileage!

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Pls help me with this
grin007 [14]

Answer:

k=8

Step-by-step explanation:

divide both sides by 11 to get nine

then subtract 1 from both sides to get

8

7 0
3 years ago
What is the value of h(−2) when h(x)=3x+1?
natali 33 [55]

Answer:

-5

Step-by-step explanation:

The answer is -5 because we have -2 as x. The function is h(x)=3x+1. 3 times -2=-6. When we add 1 to the result, we have -5 as the answer. Hope it helps!

4 0
3 years ago
Read 2 more answers
Which Data set has the smallest IQR ?
mel-nik [20]

Answer:

<h2 /><h2>The interquartile range (IQR) is the difference between the upper (Q3) and lower (Q1) quartiles, and describes the middle 50% of values when ordered from lowest to highest. The IQR is often seen as a better measure of spread than the range as it is not affected by outliers. Interquartile Range. 25% of values.</h2>

<h2 />

<h2>here your answer </h2>
8 0
3 years ago
1 + tanx / 1 + cotx =2
Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer:  x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0
3 years ago
Z varies jointly with x, and y, and z=7 when x= 2, y= 2
fomenos

Answer:

56

Step-by-step explanation:

Complete question:

Z varies jointly with x and y , x=2 and y=2, z=7. Find z when x=4 and y=8 using joint variation . (I need the problem worked out step by step)

If z varies jointly with x, and y, this is expressed as;

z = kxy

If z=7 when x= 2, y= 2

7  = k(2)(2)

7 = 4k

k = 7/4

To get z when x= 4 and y = 8

z = kxy

z =7/4 (4)(8)

z = 7*8

z = 56

Hence the value of z is 56

7 0
3 years ago
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