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2 years ago

How many positive integers, including 1, are divisors of both 40 and 72?

Mathematics

1 answer:

Nezavi [6.7K]2 years ago

8 0

Answer:

1,2,4,8

Step-by-step explanation:

1 x 40 = 40

1 x 72 = 72

2 x 20 = 40

2 x 36 = 72

4 x 10 = 40

4 x 18 = 72

8 x 5 = 40

8 x 9 = 72

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Alla [95]

Answer:

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Step-by-step explanation:

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RoseWind [281]

Answer:

$m\angle KLM=53.13^o$

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle KOM

In the triangle KOM

we have

$KO=MO=r=5\ units$

$KM=8\ units$

Applying the law of cosines

$8^2=5^2+5^2-2(5)(5)cos(KOM)$

$64=50-50cos(KOM)$

$50cos(KOM)=50-64$

$50cos(KOM)=-14$

$cos(KOM)=-14/50$

$m\angle KOM=cos^{-1}(-14/50)$

$m\angle KOM=106.26^o$

step 2

Find the measure of the arc KM

we know that

$arc\ KM=m\angle KOM$ ----> by central angle

we have

$m\angle KOM=106.26^o$

$arc\ KM=106.26^o$

step 3

Find the measure of angle KLM

we know that

The inscribed angle is half that of the arc comprising

$m\angle KLM=\frac{1}{2}[arc\ KM]$

we have

$arc\ KM=106.26^o$

substitute

$m\angle KLM=\frac{1}{2}[106.26^o]$

$m\angle KLM=53.13^o$

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Answer:

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Step-by-step explanation:

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