Lets make an equation for the line first. The slope is 3 and the y intercept is -1, so we can make the equation y = 3x - 1. Then, to figure out what sign to use (<= or >= due to solid line in graph), we replace the = sign with one and see if a coordinate in the shaded area will furfill the inequality. If it doesn't, we know it needs the other inequality sign. If it does, we have found the correct inequality. So let's try y <= 3x - 1 with the coordinate (1,1). We try it, solve, and get 1 <= 2. So, the inequality for this graph is y <= 3x - 1.
Step-by-step explanation:
24+357/1000 = 24.357. Just remember decimals are in tenths, hundredths and in this case thousandths
Responda:
Preço = $ 400
Explicação passo a passo:
Dado que:
Primeira opção :
Pagamento em 5 investimento igual
Segunda opçao :
Pagamento feito em 8 iguais. Investimento
O preço por parcela do primeiro investimento é 30 a mais do que cada um do segundo
Deixe o preço do telefone = p
Valor por prestação = x
Segunda parcela:
Preço = 8x
Primeiro :
Valor por parcela = x + 30
P = 5 (x + 30)
Preço = 5x + 150
Portanto, igualando as duas equações:
8x = 5x + 150
8x - 3x = 150
5x = 150
x = $ 50
Usando qualquer das equações de preço:
Preço = 8x
Preço = 8 * 50
Preço do telefone = $ 400
Hello there!
A positive slope is represented in a linear equation by a positive coefficient behind the x term. A positive slope means that the graph is on an increasing interval as x approaches +∞. In a more simple way, a positive slope means that the graph is going up from left to right.
A negative slope is represented in a linear equation by a negative coefficient behind the x term. A negative slope means that the graph is on a decreasing interval as x approaches +∞. In a more simple way, a negative slope means that the graph is going down from left to right.
The x intercept(s) of a graph are where the graph touches the x-axis. These are also known as the zero(s) OR solution(s) of the function.
The y intercept(s) of a graph are where the graph touches the y-axis.
I hope this helps!
Best wishes:)
