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mrs_skeptik [129]
3 years ago
12

Which of the following is equivalent to the expression below sqrt 8 - sqrt 72 + sqrt 50

Mathematics
2 answers:
mash [69]3 years ago
6 0

Answer:

Step-by-step explanation:

\sqrt{8}-\sqrt{72}+\sqrt{50} These cannot combine the way they are. The rule for adding and subtracting radicals is really picky. Not only does the index have to be the same (the little number that is sitting outside in the bend of the radical {ours is a 2, which isn't usually there, but is instead understood to be a square root}), but the radicand, the expression under the square root (or cubed root, or fourth root, etc) has to the same as well. All of our radicals are square roots, so that's good, but the radicands are all different. The first one is an 8, the next one is a 72, and the last one is a 50. BUT if we can rewrite them by simplifying them and then the radicands are the same, we're in good shape.

Simplify by taking the prime factorization of each of those numbers.

8: 4*2 and 4 is a perfect square, so we'll stop there

72: 36*2 and 36 is a perfect square, so we'll stop there

50: 25*2 and 25 is a perfect square, so we'll stop there.

Now, rewrite each one of them in terms of their prime factorization:

\sqrt{4*2}-\sqrt{36*2}+\sqrt{25*2} and then pull out each perfect square as its root:

2\sqrt{2}-6\sqrt{2}+5\sqrt{2} and now all the radicands are the same, so we can add them to get

1\sqrt{2}  or simply  \sqrt{2}

JulsSmile [24]3 years ago
3 0

Answer:

A: \sqrt{2}

Step-by-step explanation:

sqrt 8 = sqrt (2 * 2 *2 ) = 2\sqrt{2}

sqrt 72 = sqrt (2 * 2 *2 * 3 * 3 ) = 6\sqrt{2}

sqrt 50= sqrt (2 * 5 *5 ) = 5\sqrt{2}

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The weights of soy patties sold by a diner are normally distributed. A random sample of 25 patties yields a mean weight of 4.2 o
just olya [345]

Answer:

t=\frac{4.2-4}{\frac{0.5}{\sqrt{25}}}=2

The degrees of freedom are given by:

df =n-1=25-1=24

And the p value would be given by:

p_v = P(t_{24}>2) =0.0285

And since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case is significantly hiher than 4. And the claim for this case is not appropiate      

Step-by-step explanation:

Data provided

\bar X=4.2 represent the sample mean for the weigths

s=0.5 represent the sample standard deviation

n=25 sample size      

\mu_o =4 represent the value that we want to analyze

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic

p_v represent the p value for the test

System of hypothesis

We want to conduct a hypothesis in order to check if the true mean weigth is less than 4 or not, the system of hypothesis would be:      

Null hypothesis:\mu \leq 4      

Alternative hypothesis:\mu > 4      

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

Replacing the info given we got:

t=\frac{4.2-4}{\frac{0.5}{\sqrt{25}}}=2  

The degrees of freedom are given by:

df =n-1=25-1=24

And the p value would be given by:

p_v = P(t_{24}>2) =0.0285

And since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case is significantly hiher than 4. And the claim for this case is not appropiate

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3 years ago
PLEASE ANSWER!!!!!!!!!!<br><br>​
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Answer:

use air math bro it will show you all the answers to that

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