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3 years ago

15

Determine if the relationships are linear and if so are they proportional

1 answer:

Tanzania [10]3 years ago

8 0

Y=2-x^2
Vertex ( 0, 2 )
Focus : ( 0, 7/4 )
Axis of symmetry : x = 0
Directrix : y = 9/4

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Determine the value of "L"

saveliy_v [14]

Opposite sides equals to 7 and so you add 7 + 7 which equals to 14. Next you subtract 30 by 14 to get the total of the opposite side of L and itself which gets you 16 which is then divided by 2 because you have L and its opposite side which would give you 8. So L equals to 8.

Check:

7 + 7 + 8 + 8

14 + 16

30

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4 years ago

What is the value of 7r

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3 years ago

Replace the ___ with <, >, or = to make a true statement. 7^4/7^2(fraction) ___ 49

Brrunno [24]

Use this exponent property;
$\dfrac{a^m}{a^n} = a^{m-n}$

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3 years ago

What is the error for the following problem: 1.2 x 0.12 =1.44

Nana76 [90]

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Step-by-step explanation:

1.2x0.12 = 0.144

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7 0

3 years ago

During a certain24 -hour period, the temperature at time t (measured in hours from the start of the period) was T(t)=50+6t-1

fomenos

Answer:

The value of average temperature during that period= $58^{\circ}$

Step-by-step explanation:

We are given that

Temperature at time t is given by

$T(t)=50+6t-\frac{1}{3}t^2$

We have to find the average temperature during a certain 24-hour period.

We know that

Average value of function

$f_{av}=\frac{1}{b-a}\int_{a}^{b}f(x)dx$

Using the formula

Average temperature during the period

$=\frac{1}{24-0}\int_{0}^{24}(50+6t-\frac{1}{3}t^2)dt$

$=\frac{1}{24}[50t+3t^2-\frac{1}{9}t^3]^{24}_{0}$

$=\frac{1}{24}(50\times 24+3(24)^2-\frac{1}{9}(24)^3)$

$=58^{\circ}$

Hence, the value of average temperature during that period= $58^{\circ}$

3 0

3 years ago