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Nat2105 [25]
4 years ago
12

Sample mean X = 0:157 was computed from a sample of size 100 generated from a MA(1) process with mean and = 0:6, 2 = 1. Construc

t an approximate 95% CI for . Are the data compatible with the hypothesis that = 0
Mathematics
1 answer:
Snezhnost [94]4 years ago
6 0

Answer:

Step-by-step explanation:

The variance of the sample mean for an MA(1) process and procedure is in general

Var(X_{n}) = \frac{1}{n}\sum_{h = -n}^{n}(1-\frac{|h|}{n})\sigma _{n}  =\frac{1}{n}(\sigma ^{2}(1+\Theta ^{2})+2(1-\frac{1}{n})\sigma ^{2}\Theta )

Thus, in this case, we have Var(Xn) = 0.00172. An approximate 95% confidence interval for μ is then given by

\bar{x}_{n}\pm \sqrt{Var(\bar{X}_{n})} = 0.157\pm 1.96\sqrt{0.00172} = 0.157\pm 0.081

This interval does not involve the value 0, so the data are not compatible with the hypothesis that μ= 0.

You might be interested in
Find the total travel time: Depart 5:30 pm MST Arrive 9:20 pm CST.
Ivan

Answer:

2 hour 50 minutes

Step-by-step explanation:

Given data: Departure = 5:30 pm MST, Arrive = 9:20 pm CST

Note that MST is the time zone 1 hour before CST.

Let us convert MST into CST.

Departure = 5:30 pm MST = 6:30 pm CST

Total time travel = Departure – Arrival

= 9.20 pm MST – 6.30 pm MST

= 2 hour 50 minutes

Hence, total time travel is 2 hour 50 minutes.

5 0
4 years ago
2. The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 4.5. Suppose we going t
stiv31 [10]

Answer:

P(\bar X>76)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 76 we got:

z =\frac{76-75}{\frac{4.5}{\sqrt{81}}}= 2

And if we use the complement rule and the normal standard distribution or excel we got:

P(Z>2) = 1-P(Z

And we can find this using the ti 84 with the following code:

1-normalcdf(-1000, 76, 75, 0.5 )

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable who represent the score of golfers. We select a sampel size of 81.

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(\bar X>76)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 76 we got:

z =\frac{76-75}{\frac{4.5}{\sqrt{81}}}= 2

And if we use the complement rule and the normal standard distribution or excel we got:

P(Z>2) = 1-P(Z

And we can find this using the ti 84 with the following code:

1-normalcdf(-1000, 76, 75, 0.5 )

6 0
3 years ago
calculate the distance between the two points shown on the graph below give your answer correct to 2 decimal places if necessary
GenaCL600 [577]

Answer:

Find the distance between (-1, 1) and (3, 4).

This problem is solved simply by plugging our x- and y-values into the distance formula:

D=(3−(−1))2+(4−1)2−−−−−−−−−−−−−−−−−−√=

=16+9−−−−−√=25−−√=5

Sometimes you need to find the point that is exactly between two other points. This middle point is called the "midpoint". By definition, a midpoint of a line segment is the point on that line segment that divides the segment in two congruent segments.

If the end points of a line segment is (x1, y1) and (x2, y2) then the midpoint of the line segment has the coordinates:

(x1+x22,y1+y22)

4 0
3 years ago
In how many ways can a committee of four be chosen from five married couples if a husband and wife cannot both be selected?
Neko [114]

One of the approaches:

Each couple can send only one "representative" to the committee. Let's see in how many ways we can choose 3 couples (as there should be 3 members) out of 4 to send only one "representatives" to the committee: 4C3=4.

But each of these 3 couples can send two persons (husband or wife): 2*2*2=2^3=8.

Total # of ways: 4C3*2^3=32.

hope it helped a bit
3 0
3 years ago
A table shaped like a solid cube needs to painted. All six faces of the table must be painted. The edge length of the table is 1
Nataly_w [17]
7.2

1.2 x 6 = 7.2

hope this helps!
8 0
3 years ago
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