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ZanzabumX [31]
2 years ago
13

Make up an equation for a quadratic function whose graph satisfies the given condition. Use whatever form is most convenient. i.

Has a vertex at (−2,−5). ii. Has a y-intercept at (0, 6). iii. Has x-intercepts at and (3, 0) and (5, 0). iv. Has x-intercepts at the origin and (4, 0). v. Goes through the points (4, 2) and (1, 2).
Mathematics
1 answer:
vodomira [7]2 years ago
5 0

Answer:

yx6

Step-by-step explanation:

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5 0
3 years ago
System of Equations: Solve for (x,y) given the system of linear equations "X 1 point
Elenna [48]

Answer:

  (x, y) = (4, 0)

Step-by-step explanation:

It looks like you want to solve ...

  • x - y = 4
  • x + y = 4

Adding the two equations gives ...

  2x = 8

  x = 4 . . . . divide by 2

Then ...

  y = 4 - x = 0

The solution is (x, y) = (4, 0).

_____

If you think about what you're seeing when you read the equations, you realize that adding or subtracting y gives the same result. Hence y=0 and x=4.

8 0
2 years ago
What is the solution of the equation 4x + 3y = 12 7x + 5y = 26
malfutka [58]
The solution would be B) (18,-20)
4 0
3 years ago
5
stellarik [79]

Answer:

(0,2),(1,6),(−2,−6) are solutions

8 0
2 years ago
Solve <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4%20%7D%7B4%20-%20x%7D%20%3D%20%5Cfrac%7B5%7D%7B%284%20%2B%20x%29%7D%20
lisov135 [29]

Domain:\\4-x\neq0\ \wedge\ 4+x\neq0\\x\neq4\ \wedge\ x\neq-4\\\\\dfrac{4}{4-x}=\dfrac{5}{4+x}\qquad\text{cross multiply}\\\\4(4+x)=5(4-x)\qquad\text{use distributive property}\\\\(4)(4)+(4)(x)=(5)(4)+(5)(-x)\\\\16+4x=20-5x\qquad\text{subtract 16 from both sides}\\\\4x=4-5x\qquad\text{add 5x to both sides}\\\\9x=4\qquad\text{divide both sides by 9}\\\\\boxed{x=\dfrac{4}{9}}

6 0
2 years ago
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