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svet-max [94.6K]
4 years ago
8

Given the system of equations, what is the value of the system determinant? x + y = 8 x - y = 10 0 -1 -2

Mathematics
2 answers:
kkurt [141]4 years ago
8 0

Each X and Y in the equations don't have a number in front of them so they are all considered 1.

D = 1*(-1) - 1*(-1) = -1 -1 = -2

The answer is -2

Bond [772]4 years ago
5 0

Answer:

-2

Step-by-step explanation:

We need to set up the matrix to find the determinant

a  b

c  d

To find the determinant we take ad - bc

x + y = 8

x - y = 10

Take the coefficients of the x and y terms

1  1

1 -1

1 (-1) - (1) *1

-1 - 1

-2

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Answer

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2

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3 years ago
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Make t the subject of the formula: S = at + bt
riadik2000 [5.3K]
To make t the subject is basically isolating t

S = at + bt
We see on the right side that t is common, so we factor it out.

S = t(a + b)
Divide by (a+b) to isolate t

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We are left with the answer:
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8 0
3 years ago
Read 2 more answers
What is the equation of the asymptote for the exponential function shown on the graph?
lakkis [162]

Answer:

B) y=0

Step-by-step explanation:

The exponential function shown has a horizontal asymptote at the line y=0, which means that y will approach 0 as the value of x decreases. Therefore, B is correct.

7 0
3 years ago
Help me please! <br><br> a = 3, b = 5, and c = 7. What is m&amp;Bº to the nearest tenth?
Anastaziya [24]

Answer: m∡B°=38,2°.

Step-by-step explanation:

a=3,  b=5,  c=7  ∡B°=?

b^2=a^2+c^2-2*a*ccosB^0\\2*a*c*cosB^0=a^2+c^2-b^2\\cosB^0=\frac{a^2+c^2-b^2}{2*a*c} \\cosB^0=\frac{3^2+7^2-5^2}{2*3*7} \\cosB^0=\frac{9+49-25}{2*3*7} \\cosB^0=\frac{33}{42} \\cosB^0=\frac{11}{14}\\

m∡B°=arccos(\frac{11}{14})

m∡B°≈38,2°.

Good luck!

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2 years ago
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