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insens350 [35]
3 years ago
10

Which figure has both lines of symmetry and symmetry and rotation symmetry?​

Mathematics
2 answers:
nydimaria [60]3 years ago
6 0

Answer:

the first one is one line of symmetry

Sedaia [141]3 years ago
3 0

Answer:

Pentagon

Step-by-step explanation:

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PLEASE help me ! 10 points + brainliest :))
Yanka [14]

Answer:

200

Step-by-step explanation:

Mark me as brainliest

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3 years ago
Three electrical appliances each have power ratings of
Natasha_Volkova [10]
30+8/5=31.6 you have to break the whole question down to get the answer.
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Read 2 more answers
PLEASE HELP LAST QUESTION
igomit [66]

ANSWER:

a) y = 15x + 75

b) 50 weeks

EXPLANATION:

P A R T   A

2 weeks, 105 dollars --> (2, 105)

5 weeks, 150 dollars --> (5, 150)

<u />

<u>if we use slope intercept form (y=mx+b), we must:</u>

1) find the slope

y2 - y1 -->> 150 - 105 = 45

x2 - x1 -->> 5 - 2 = 3

45/3 = 15

2) find the y intercept

y = 15x + b -->> 150 = 15 (5) + b -->> 150 = 75 + b -->> 75 = b

--------------------------------------------------------------------------------------------

P A R T   B

y = 15x + 75 (substitute the y with 825 because that is the goal)

825 = 15x + 75 (solve normally)

750 = 15x

50 = x

5 0
3 years ago
A physician's assistant measures a child and finds his height is 41 in.
Ludmilka [50]

Answer:

He grew 4 inches since his last visit.

Step-by-step explanation:

41 - 38 = 4

3 0
3 years ago
Explain why a quadratic equation with a positive discriminant has two real solutions, a quadratic equation with a negative discr
Bad White [126]

Answer:

A quadratic equation can be written as:

a*x^2 + b*x + c = 0.

where a, b and c are real numbers.

The solutions of this equation can be found by the equation:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

Where the determinant is D = b^2 - 4*a*c.

Now, if D>0

we have the square root of a positive number, which will be equal to a real number.

√D = R

then the solutions are:

x = \frac{-b +- R }{2*a}

Where each sign of R is a different solution for the equation.

If D< 0, we have the square root of a negative number, then we have a complex component:

√D = i*R

x = \frac{-b +- C*i }{2*a}

We have two complex solutions.

If D = 0

√0 = 0

then:

x = \frac{-b +- 0}{2*a} = \frac{-b}{2a}

We have only one real solution (or two equal solutions, depending on how you see it)

3 0
3 years ago
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