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8_murik_8 [283]
3 years ago
15

Help plz due in a hour

Mathematics
1 answer:
melamori03 [73]3 years ago
4 0
I hope this is helpful

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Write the property that matches the equation.<br> 3+(4+7)=(3+4)+7
miss Akunina [59]

Answer:

associative property

Step-by-step explanation:

3 0
3 years ago
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An umbrella has 12 evenly spaced ribs. If viewed as a flat circle of radius 11 units,
erica [24]

Answer:

Area = 121pi/12

~= 31.66 sq units

Step-by-step explanation:

They are talking about looking at an umbrella like its a circle. The radius is 11 units. That is from the center to the edge.

Consecutive means "in a row" or "next to each other" The 12 "ribs" are the like skeleton structure in the umbrella. But they cut the umbrella into 12 areas. They are asking for the area of one "slice". It is 1/12 of the area of the whole circle.

Area of a circle is

A = pi × r^2

Area of one slice is 1/12 of the whole.

A(1 slice)

= 1/12× pi × r^2

See image.

4 0
2 years ago
HOW DO THE PROPERTIES OF A DILATION TRANSFORMATION DIFFER FROM THE OTHER TRANSFORMATIONS YOU HAVE LEARNED ABOUT?
Alexxandr [17]

It differs because dilation changes the shape but not the orientation or place the shape is located.

7 0
3 years ago
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One of the solutions of the system of equations shown in the graph has an x-value of –4. What is its corresponding integer y-val
jeka57 [31]
The solution is (-4, -1
7 0
3 years ago
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When the solutions are going to be complex, which methods can be used to solve quadratic equations?
yKpoI14uk [10]
You could complete the square to state the vertex. 
You could use the quadratic equation to find the roots (which are complex). 

Try an example that will require both.

y = x^2 + 2x + 5

Step One
Get the graph. That's included below.

Step Two
Provide the steps for completing the square.
Note: we should get (-1,4)

y= (x^2 +2x ) + 5
y = (x^2 +2x + 1) + 5 - 1
y = (x +1)^2 + 4

The vertex is at (-1,4)

Step Three
Find the roots. Use the quadratic equation. Note that the graph shows us that the equation never crosses or touches the x axis. The roots are complex.

\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a}

a = 1
b = 2
c = 5

\text{x = }\dfrac{ -2 \pm \sqrt{2^{2} - 4*1*5 } }{2}
\text{x = }\dfrac{ -2 \pm \sqrt{4 - 20 } }{2}
\text{x = }\dfrac{ -2 \pm \sqrt{-16 } }{2}
\text{x = }\dfrac{ -2 \pm 4i }{2}
x = -1 +/- 2i

x1 = -1 + 2i
x2 = -1 - 2i And we are done.


7 0
3 years ago
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