All categories

3 years ago

How do i solve -(1+7x)-6(-7-x)=36

Mathematics

2 answers:

kondor19780726 [428]3 years ago

8 0

$-(1+7x)-6(-7-x)=36\\\\-1-7x+42+6x=36\\\\-7x+6x=36+1-42\\\\-x=-5\\\\x=5$

Ksju [112]3 years ago

6 0

-(1+7x)-6(-7-x)=36 -- expand brackets
-1-7x+42+6x=36 -- combine like terms
41-x=36 -- add x to both sides and subtract 36 from both sides
5=x

x=5

You might be interested in

Armando got a job selling bags of peanuts at the local art festival. He is paid a fixed amount of $320 per

skelet666 [1.2K]

0.67n + 320

=(0.67 * 430) + 320

= 288.1 + 320

= $608.1

0.67n + 320 = 728.70

0.67n = 728.70 - 320

0.67n = 408.7

n = 408.7 / 0.67

n = 610 Bags of peanuts

6 0

2 years ago

Pedro and Paola are married and file their taxes jointly.Paola's taxable income was $55,675

uysha [10]

Answer:

Pedro and paola don't seem so happy together

4 0

2 years ago

Victoria is going to a carnival that has games and rides. Each game costs $2 and each ride costs $4. Victoria spent $16 altogeth

TiliK225 [7]

Answer:

2 rides & 4 games

Step-by-step explanation:

2 rides=$8

4 games=$8

8+8=$16

8 0

2 years ago

Rearrange the formula d = m/ v for v.

RUDIKE [14]

If you are looking for volume you want v by itself so your formula would look like this : d*m=v
hope this helps

4 0

3 years ago

Read 2 more answers

Verify identity list steps. Cot(t)(1-cos^2(t))=cos(t)sin(t)

storchak [24]

Remember: We have to work from either the LHS or the RHS.
(Left hand side or the Right hand side)

You should already know this:

$\huge{Cot(t) = \frac{1}{tan(t)} = \frac{1}{\frac{sin(t)}{cos(t)}} = 1\div \frac{sin(t)}{cos(t)} = 1\times \frac{cos(t)}{sin(t)}=\boxed{\frac{cos(t)}{sin(t)}}$

You should also know this:

$sin^2(t) + cos^2(t) = 1\\\\\boxed{sin^2(t)} = 1 - cos^2(t)$

So plugging in both of those into our identity, we get:

$\frac{cos(t)}{sin(t)}\cdot sin^2(t) = cos(t)\cdot sin(t)$

Simplify the denominator on the LHS (Left Hand Side)

We get:

$cos(t) \cdot sin(t) = cos(t) \cdot sin(t)$

LHS = RHS

Therefore, identity is verified.

4 0

3 years ago