Find the area of the shaded segment below. Use 3.14 for pi.

The number of bacteria in a refrigerated food product is given by N ( T ) = 27 T 2 − 180 T + 100 N(T)=27T2-180T+100, 7 < T &l

NeX [460]

Answer:

$N(T(t))=432t^2-374.4t-118.88$

The number of Bactria after 5.8 hours is 12242.

Step-by-step explanation:

The number of bacteria in a refrigerated food product is given by

$N(T)=27T^2-180T+100$

where, T is the temperature of the food.

When the food is removed from the refrigerator, then the temperature is given by

$T(t)=4t+1.6$

We need to find the composite function N(T(t)).

$N(T(t))=N(4t+1.6)$

$N(T(t))=27(4t+1.6)^2-180(4t+1.6)+100$

$N(T(t))=432t^2+345.6t+69.12-720t-288+100$

$N(T(t))=432t^2-374.4t-118.88$

where N(T(t)) is the number of bacteria after t hours.

Substitute t=5.8 in the above function.

$N(T(5.8))=432(5.8)^2-374.4(5.8)-118.88$

$N(T(5.8))=14532.48-2290.4$

$N(T(5.8))=12242.08$

$N(T(5.8))\approx 12242$

Therefore, the number of Bactria after 5.8 hours is 12242.

7 0

4 years ago

What is 126 billion divied by 108.2 billion

LUCKY_DIMON [66]

the answer is 0.00116451016

hope it helped :)

4 0

3 years ago

Read 2 more answers

Use undetermined coefficient to determine the solution of:y"-3y'+2y=2x+ex+2xex+4e3x

Kitty [74]

First check the characteristic solution: the characteristic equation for this DE is

r ² - 3r + 2 = (r - 2) (r - 1) = 0

with roots r = 2 and r = 1, so the characteristic solution is

y (char.) = C₁ exp(2x) + C₂ exp(x)

For the ansatz particular solution, we might first try

y (part.) = (ax + b) + (cx + d) exp(x) + e exp(3x)

where ax + b corresponds to the 2x term on the right side, (cx + d) exp(x) corresponds to (1 + 2x) exp(x), and e exp(3x) corresponds to 4 exp(3x).

However, exp(x) is already accounted for in the characteristic solution, we multiply the second group by x :

y (part.) = (ax + b) + (cx ² + dx) exp(x) + e exp(3x)

Now take the derivatives of y (part.), substitute them into the DE, and solve for the coefficients.

y' (part.) = a + (2cx + d) exp(x) + (cx ² + dx) exp(x) + 3e exp(3x)

… = a + (cx ² + (2c + d)x + d) exp(x) + 3e exp(3x)

y'' (part.) = (2cx + 2c + d) exp(x) + (cx ² + (2c + d)x + d) exp(x) + 9e exp(3x)

… = (cx ² + (4c + d)x + 2c + 2d) exp(x) + 9e exp(3x)

Substituting every relevant expression and simplifying reduces the equation to

(cx ² + (4c + d)x + 2c + 2d) exp(x) + 9e exp(3x)

… - 3 [a + (cx ² + (2c + d)x + d) exp(x) + 3e exp(3x)]

… +2 [(ax + b) + (cx ² + dx) exp(x) + e exp(3x)]

= 2x + (1 + 2x) exp(x) + 4 exp(3x)

… … …

2ax - 3a + 2b + (-2cx + 2c - d) exp(x) + 2e exp(3x)

= 2x + (1 + 2x) exp(x) + 4 exp(3x)

Then, equating coefficients of corresponding terms on both sides, we have the system of equations,

x : 2a = 2

1 : -3a + 2b = 0

exp(x) : 2c - d = 1

x exp(x) : -2c = 2

exp(3x) : 2e = 4

Solving the system gives

a = 1, b = 3/2, c = -1, d = -3, e = 2

Then the general solution to the DE is

y(x) = C₁ exp(2x) + C₂ exp(x) + x + 3/2 - (x ² + 3x) exp(x) + 2 exp(3x)

4 0

3 years ago

If "x" represents -8 and "z" represents -11, what is x - (-z)?

Arisa [49]

Answer:

It equals 3, but if you add two negatives inside of the parenthesis, then it equals -19.

Step-by-step explanation:

You have to plug in the numbers where the variables are, so it would be -8-(-11).

8 0

3 years ago

The temperature is 16 degrees F in the morning and drops to -15 degrees F in the evening what is the difference between these te

Arturiano [62]

16 - (-15) = 16 + 15 = 31...difference of 31 degrees

8 0

3 years ago